Which of the following quadrilaterals have diagonals that are perpendicular to each other? Check all that apply.

Mathematics

1 answer:

mars1129 [50]3 years ago

4 0

Answer: Option B and option D.

Step-by-step explanation:

We know that a quadrilateral is a 2-dimensional closed shape that has four sides.

By definition the diagonals of a quadrilateral are the lines that connect two non-adjacent vertices.

The following quadrilaterals have diagonals that are perpendicular to each other (also known as perpendicular bisector diagonals), which means that they form four angles of 90 degrees (right angles): <em>Rhombus and Square.</em>

Therefore the answers are: the option B and the option D.

You might be interested in

Someone help me please and thank you!! ASAP :(

pantera1 [17]

<h3>Answer: Choice D) </h3>

Work Shown:

$(f+g)(x) = f(x)+g(x)\\\\(f+g)(x) = \frac{x-23}{x^2+9x-36}+\frac{1}{x+12}\\\\(f+g)(x) = \frac{x-23}{(x+12)(x-3)}+\frac{1(x-3)}{(x+12)(x-3)}\\\\(f+g)(x) = \frac{x-23+1(x-3)}{(x+12)(x-3)}\\\\(f+g)(x) = \frac{x-23+x-3}{x^2+9x-36}\\\\(f+g)(x) = \frac{2x-26}{x^2+9x-36}\\\\$