Answer:
The person would have to play 2 games for the two bowling alleys to cost the same amount
Step-by-step explanation:
Assume that the number of games that makes the two costs equal is x
∵ A bowling alley charges $2.50 per game plus $4 to rent shoes
∵ The number of games is x
∴ The cost = 2.50x + 4
∵ A second bowling alley charges $4 per game plus $1 to rent shoes
∵ The number of games is x
∴ The cost = 4x + 1
∵ They have the same cost
→ Equate the 2 expressions above
∴ 4x + 1 = 2.50x + 4
→ Subtract 2.50x from both sides
∵ 4x - 2.50x + 1 = 2.50x - 2.50x + 4
∴ 1.50x + 1 = 4
→ Subtract 1 from both sides
∵ 1.50x + 1 - 1 = 4 - 1
∴ 1.50x = 3
→ Divide both sides by 1.50
∴ x = 2
∴ The person would have to play 2 games for the two bowling alleys to
cost the same amount
Step-by-step explanation:
<u>Let us assume that:</u>
<u>Therefore, the equation becomes:</u>
<u>Now substitute the value of u. We get:</u>
<u>Therefore:</u>
★ <u>Which is our required answer.</u>
(a + b)² = a² + 2ab + b²
(a - b)² = a² - 2ab + b²
a² - b² = (a + b)(a - b)
(a + b)³ = a³ + 3ab(a + b) + b³
(a - b)³ = a³ - 3ab(a - b) - b³
a³ + b³ = (a + b)(a² - ab + b²)
a³ - b³ = (a - b)(a² + ab + b²)
(x + a)(x + b) = x² + (a + b)x + ab
(x + a)(x - b) = x² + (a - b)x - ab
(x - a)(x + b) = x² - (a - b)x - ab
(x - a)(x - b) = x² - (a + b)x + ab
