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CaHeK987 [17]
3 years ago
11

If f(x)=3x-15, then f^-1(x) = solve for x please

Mathematics
1 answer:
amid [387]3 years ago
5 0
1.  Replace f(x) with y:  y = 3x - 15
2.  Interchange x and y:  x = 3y - 15
3.  Solve this for y:  3y = x + 15, and y = (x + 15)/3
4.  Replace y with 

   -1                -1
 f   (x):           f   (x) = (x + 15) / 3            (answer)
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Isaac wants the equation below to have no solution when the missing number is placed in the box.
MatroZZZ [7]

Answer: 4

Step-by-step explanation: To have an equation with no solution you have to get something like 0=1 meaning you have to remove all the variables. In this equation you would distribute to get xy+2y+2x=2x+12+4x where y is the missing number. then combining like terms you get xy+2x+2y=6x+12. Subtracting 2x from both sides you get xy+2y=4x+12. Now to get the variables gone y has to be 4 so that the variables to cancel out. By plugging in 4 you can see this works; 4x+8=4x+12 and by subtracting 4x from both sides you get 8=12 which is not true meaning there is no solution.

8 0
3 years ago
Read 2 more answers
Please help !
nadya68 [22]

Answer:

r(-2)= -5

r(0)= -7

r(5)= -12

6 0
2 years ago
What is the volume of the composite figure?
Romashka [77]

Answer:

1428 in³

Step-by-step explanation:

To find the volume of this figure, we will need to use two formulas. The volume of a Rectangular Prism (A= l * w * h) and volume of a triangular prism. A = \frac{1}{2}(b*h)

If we look at the Rectangular Prism, we can find that l = 17, w = 8, and h = 5. Multiply these to find the volume:

17 × 8 × 5 = 680 in³.

Solving for the triangular prism gives us:

A = 1/2 (11 ×  8 × 17)

A = 748.

Add these two volumes to find the volume of the composite figure:

748 + 680 = 1428 in³

5 0
3 years ago
A semicircle with diameter PQ sits on an isosceles triangle PQR to form a region shaped like a two-dimensional ice- cream cone,
Ksivusya [100]

The limit of a(x)/b(x) as x approaches 0 is gotten as;

lim a(x)/b(x); x→0 = 0

  • The image showing the semi circle and isosceles triangle is missing and so i have attached it.

  • Formula for <em>area</em> of a semi circle is;

a(x) = A = ¹/₂πr²

  • <em>Area</em> of triangle is;

b(x) = A =  ¹/₂ × base × height

  • From the image, ∠PQR = θ

Thus; a(x) = ¹/₂π(10 sin (θ/2))²

a(x) =  ¹/₂π(100 sin² (θ/2))

Similarly;

b(x) =  ¹/₂(20 sin (θ/2)) × (10 cos (θ/2))

b(x) = 100 sin (θ/2) cos (θ/2)

  • Thus;

a(x)/b(x) = ¹/₂π(100 sin² (θ/2)) ÷ 100 sin (θ/2) cos (θ/2)

100 will cancel out and the sin (θ/2) at the denominator will be eradicated

upon further simplification to give;

a(x)/b(x) = ¹/₂π(sin (θ/2)) ÷ cos (θ/2)

In trigonometry, we know that; tan θ = sin θ/cos θ

Thus;

a(x)/b(x) = ¹/₂π(sin (θ/2)) ÷ cos (θ/2) =  ¹/₂π(tan (θ/2))

We want to find the limit as θ approaches <em>zero.</em>

Thus;

lim θ → 0 =  ¹/₂π(tan (0/2))

⇒ ¹/₂π tan 0

⇒ 0

Read more at; https://brainly.in/question/9387458

3 0
2 years ago
3(20 + 4) =<br> Help me pleases
valentinak56 [21]

Answer:

72 is your answer mate...

8 0
4 years ago
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