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Aleonysh [2.5K]

3 years ago

9

Which constants could each equation be multiplied by to eliminate the x-variable using addition in this system of equations? 2 x

+ 3 y = 25. Negative 3 x + 4 y = 22.
1.The first equation can be multiplied by –3 and the second equation by 2.
2. The first equation can be multiplied by –4 and the second equation by 2.
3. The first equation can be multiplied by 3 and the second equation by 2.
4. The first equation can be multiplied by 4 and the second equation by –3.

2 answers:

lions [1.4K]3 years ago

8 0

Answer:

hes right

Step-by-step explanation:

Sever21 [200]3 years ago

4 0

Answer:

3. The first equation can be multiplied by 3 and the second equation by 2.

Step-by-step explanation:

2 x + 3 y = 25 (1)

-3 x + 4 y = 22 (2)

Multiply equation (1) by 3 and (2) by 2.

3(2x) = 6x

2(-3x) = -6x

When you add the two equations, x will get cancelled last

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can someone help me figure this out?? My sisters at work rn she usually helps me with algerbra pleasee help!

ANEK [815]

Answer:

its the last one hun

Step-by-step explanation:

5 0

2 years ago

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denis23 [38]

Hello!

<u><em>Answer: </em></u>

<u><em>1. =-6</em></u>

<u><em>2. =39</em></u>

<u><em>3. =-603</em></u>

_________________________________________________

Explanation: This question's it's about the order of operations. It stands for p-parenthesis, e-exponents, m-multiply, d-divide, a-add, and s-subtract. It can also go left to right. (PEMDAS)

1. -4(3-1)+2

Do parenthesis first.

$(3-1)=2$

$-4*2+2$

Then do multiply left to right.

$-4*2=-8$

Add left to right.

$-8+2$

$8-2=6$

*Answer should be have negative sign.*

Answer: → $\boxed{=-6}$

______________________________________________________

2. 3⋅[(30−8)÷2+2]

Do parenthesis first.

$(30-8)=22$

$22/2+2$

Then divide left to right.

$22/2=11$

Add left to right.

$11+2=13$

Multiply left to right.

$3*13=39$

*Answer should be have positive sign.*

Answer: → $\boxed{=39}$

_____________________________________________________

3. 14(1-23)2+13

Do parenthesis first.

$(1-23)=-22$

$14(-22)*2+13$

Then, you multiply left to right.

$14(-22)=-308$

$-308*2=-616$

Add/subtract left to right.

$-616+13$

$616-13=603$

*The answer must be have a negative sign*

Answer: → $\boxed{=-603}$

____________________________________________________________

Hope this helps!

Thank you!

Have a great day!

-Charlie

7 0

3 years ago

Can u guys help me w number 5 U can answer 6 if u want too

Grace [21]

Answer:

5. Slope: 2

y-intercept:(0,-6)

y=2x-6

6. Slope:1

y-intercept:(0,-1)

y=x-1

8 0

2 years ago

Find the vertex of the parabola. y= -4x^2+24x-35<br><br> Answer ASAP

exis [7]

Answer:

(3,1)

Step-by-step explanation:

y=-4x^2+24x-35

x-intercept of the vertex formula:

v=-b/2a

a=-4

b=24,

c=-35

v = - 24/2(-4)

v = -24/-8

v = 3

substitute x as v

y= -4(3)^2 + 24(3) - 35

y= -4(9) + 72 - 35

y = -36 +72 - 35

y = 36 - 35

y = 1

therefore the vertex is

(3,1)

7 0

2 years ago

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Work out the size of one of the exterior angles

hodyreva [135]

<u>Given</u><u> </u><u>Information</u><u> </u><u>:</u><u>-</u>

⠀

A polygon with 10 sides ( Decagon )

⠀

<u>To</u><u> </u><u>Find</u><u> </u><u>:</u><u>-</u>

⠀

The value of one of the exterior angles

⠀

<u>Formula</u><u> </u><u>Used</u><u> </u><u>:</u><u>-</u>

⠀

$\qquad \diamond \: \underline{ \boxed{ \pink{ \sf Exterior ~angle = \dfrac {360^\circ}{no. ~of~sides}}}} \: \star$

⠀

<u>Solution</u><u> </u><u>:</u><u>-</u>

⠀

Putting the given values, we get,

⠀

$\sf \dashrightarrow Exterior ~angle = \dfrac{360 ^\circ}{10} \: \: \\ \\ \\ \sf \dashrightarrow Exterior ~angle = \frac{36 \cancel{0}^\circ}{ \cancel{10}} \: \: \\ \\ \\ \sf \dashrightarrow Exterior ~angle = \underline{ \boxed{ \frak{ \red{36^\circ}}}} \: \star \\ \\$

Thus, the value of the exterior angles of a Decagon is 36°.

⠀

$\underline{ \rule{227pt}{2pt}} \\ \\$

8 0

2 years ago

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