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Aleonysh [2.5K]
4 years ago
9

Which constants could each equation be multiplied by to eliminate the x-variable using addition in this system of equations? 2 x

+ 3 y = 25. Negative 3 x + 4 y = 22.
1.The first equation can be multiplied by –3 and the second equation by 2.
2. The first equation can be multiplied by –4 and the second equation by 2.
3. The first equation can be multiplied by 3 and the second equation by 2.
4. The first equation can be multiplied by 4 and the second equation by –3.
Mathematics
2 answers:
lions [1.4K]4 years ago
8 0

Answer:

hes right

Step-by-step explanation:

Sever21 [200]4 years ago
4 0

Answer:

3. The first equation can be multiplied by 3 and the second equation by 2.

Step-by-step explanation:

2 x + 3 y = 25 (1)

-3 x + 4 y = 22 (2)

Multiply equation (1) by 3 and (2) by 2.

3(2x) = 6x

2(-3x) = -6x

When you add the two equations, x will get cancelled last

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A car is travelling at exactly 6 miles per hour and accelerates at a constant rate to exactly 65 miles per hour.
vichka [17]

Answer:

14878.04878miles/hours^2

Step-by-step explanation:

Let's find a solution by understanding the following:

The acceleration rate is defined as the change of velocity within a time interval, which can be written as:

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A=acceleration rate

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Using the problem's data we have:

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Using the acceleration rate equation we have:

A=(65miles/hour - 6miles/hour)/14.8seconds, but look that velocities use 'hours' unit while 'T' uses 'seconds'.

So we need to transform 14.8seconds into Xhours, as follows:

X=(14.8seconds)*(1hours/60minutes)*(1minute/60seconds)

X=0.0041hours

Using X=0.0041hours in the previous equation instead of 14.8seconds we  have:

A=(65miles/hour - 6miles/hour)/0.0041hours

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