Given the functions, f(x) =3x -2 and g(x) = x+2/3, complete parts 1 and 2.

1 answer:

8 0

F(g(x)) = 3(x+2/3) - 2
Now, distribute the 3:
3x + 2 - 2
f(g(x)) = 3x
g(f(x)) = (3x - 2) + 2/3
Get a common denominator to add the faction
-6/3 + 2/3
g(f(x)) = 3x - 4/3

The relationship between the two composition functions is that they are commutative or permutable.

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15 – 0.5(4x – 2) + 4x = 17

loris [4]

Answer:

$\large\boxed{x=\dfrac{1}{2}=0.5}$

Step-by-step explanation:

$15-0.5(4x-2)+4x=17\qquad\text{use the distributive property}\ a(b+c)=ab+ac\\\\15+(-0.5)(4x)+(-0.5)(-2)+4x=17\\\\15-2x+1+4x=17\qquad\text{combine like terms}\\\\(-2x+4x)+(15+1)=17\\\\2x+16=17\qquad\text{subtract 16 from both sides}\\\\2x+16-16=17-16\\\\2x=1\qquad\text{divide both sides by 2}\\\\\dfrac{2x}{2}=\dfrac{1}{2}\\\\x=\dfrac{1}{2}$

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3 years ago

Find the slope and standard form of the line that passes through the points (3, 6) and (4, 5).

qwelly [4]

Answer:

B) m = -1 , x + y = 9

Step-by-step explanation:

7 0

2 years ago

How to find the limit of that question

jeka94

Factor the numerator using difference of cubes:
$a^3 - b^3 = (a-b)(a^2 +ab+b^2)$
a = x
b = 2

$\frac{x^3 - 8}{x-2} = \frac{(x-2)(x^2 +2x+4)}{x-2} = x^2 +2x+4$

Now you can evaluate limit as x=2.
$\lim_{x \to 2} (x^2 +2x+4) = 2^2 +2(2)+4 = 12$