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2 years ago

11

Mr. Wilson drives 450 miles in seven hours. At this rate, about how many miles does he drive in six hours? A) 101 B) 254 C) 340

D) 386

1 answer:

Deffense [45]2 years ago

5 0

I think D is the answer hope this helps

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8. Find the measure of the interior angles. *

tatiyna

180/3=60
Each angle is 60 degrees.

8 0

2 years ago

What is the justification for each step in solving the inequality?

alekssr [168]

$HELLO ANNA!!$

Given inequality
=> −2(x+1)≥3x+8
=>
$- 2x - 2 \geqslant 3x + 8 \\ \\ add \: 2 \: in \: both \: sides \\ \\ - 2x \geqslant 3x + 10 \\ \\ subtract \: with \: - 3x \: in \: both \: sides \: \\ \\ - 5x \geqslant 10 \\$

now multiply with - on both sides.

As we know now sign will change
=> 5x >_ -10

Now divide by 5 on both sides
=> x >_ -2
HOPE IT HELPED YOU.

4 0

2 years ago

Read 2 more answers

Here you go this is the full question please help

hammer [34]

I don’t see anything is there supposed to be a picture or?

8 0

1 year ago

Read 2 more answers

wind resistance varies jointly as an objects surface area and velocity. if an object traveling at 55 miles per hour with a surfa

nikdorinn [45]

Answer:

25 miles per hour

Step-by-step explanation:

Given

$W = Wind\ resistance$

$A = Surface\ Area$

$V = Velocity$

The joint variation can be represented as:

$W\ \alpha\ A*V$

Where:

$V = 55; A = 20; W = 220$

Required

Find V, when: $A = 55; W = 275$

We have:

$W\ \alpha\ A*V$

Express as an equation

$W= k *A*V$

Where k is the constant of variation

Make k the subject

$k = \frac{W}{A*V}$

When: $V = 55; A = 20; W = 220$

We have:

$k = \frac{220}{20 *55 }$

$k = \frac{220}{1100}$

$k = 0.2$

When: $A = 55; W = 275$

We have:

$k = \frac{W}{A*V}$

Substitute: $A = 55; W = 275$ and $k = 0.2$

$0.2 = \frac{275}{55 * V}$

Make V the subject

$V= \frac{275}{55 * 0.2}$

$V= \frac{275}{11}$

$V= 25$

3 0

2 years ago

Find the distance between each pair of points.<br> 3) (6, -2), (8, -3)<br> 4) (7,-8), (-8, 2)

castortr0y [4]

Answer:

3) $\sqrt{5}$

4) $5\sqrt{13}$

Step-by-step explanation:

distance between two points:

$d = \sqrt{(x_{2}-x_{1})^{2}+ (y_{2}-y_{1})^{2}}$

we have:

3) (6, -2), (8, -3)

$x_{1} = 6$

$y_{1} =-2$

$x_{2} = 8$

$y_{2} =-3$

so we have:

$d =\sqrt{(8-6)^{2}+ (-3-(-2))^{2}}\\\\d =\sqrt{(2)^{2}+ (-1)^{2}}\\\\d = \sqrt{4+ 1}\\\\d=\sqrt{5}$

4) (7,-8), (-8, 2)

$x_{1} = 7$

$y_{1} =-8$

$x_{2} =-8$

$y_{2} =2$

$d =\sqrt{(-8-7)^{2}+ (2-(-8))^{2}}\\\\d =\sqrt{(-15)^{2}+ (10)^{2}}\\\\d = \sqrt{225+ 100}\\\\d=\sqrt{325}\\\\d=5\sqrt{13}$

3 0

2 years ago