Power is the work performed divided by time in seconds. The work is the force times distance:

the time in seconds is 60*11+30=690s so the power is

So choice B
The area under the graph. W = f d cos(theta), so you want the number that is force times displacement, which corresponds to the area under the graph.
You said T = 2 · π · √(L / g)
(I think that's the formula for the full-swing period of a simple pendulum.)
Divide each side by 2π : T/2π = √(L / g)
Square each side: (T/2π)² = L / g
Multiply each side by ' g ' : L = g · (T/2π)²