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3 years ago

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Plsase help meeeeeee

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Law Incorporation [45]3 years ago

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Answer:

It's A

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Technician A says that galvanic activity is the result of a poor ground connection. Technician B says that electrolysis can occu

Drupady [299]

Answer:

Only B is correct.

Explanation:

Electrolysis and galvanic activity are two different ways of the passage of electricity. Electrolysis occurs at a spontaneous reaction, and galvanic activity needs an external force to happen.

For example, a cell works by a redox reaction, in which a material reduces (gain electrons), and the other oxides (loses electrons). As higher is the standard reduction potential of a material, as easy is to it to reduces. Thus, if a cell works with the reduction happens with the material with low standard reduction potential, then it works by galvanic activity.

When electronics are connected to the house system, it's necessary to do the ground connection, which will allow the electrons that are dissipated to go to the earth. So, it is done incorrectly, the electrons flow to the equipment, which they natural path. So, the electrolysis can occur with a poor ground connection.

7 0

4 years ago

What is physics???????????

KiRa [710]

Physics is everything in life technically. and there is a lot of types of physics. also it is math and reading mixed together.

4 0

3 years ago

In this equation Fs=-kx, Fs means:

nydimaria [60]

Answer:

C Restoring Force

Explanation:

Given data

Fs=-kx

According to Hokes Law, provided the elasticity of an elastic material is not exceeded the extension xis directly proportion to the applied force F

From the expression, F represent the Restoring Force in Newton

5 0

3 years ago

A counterflow double-pipe heat exchanger is used to heat water from 20°C to 80°C at a rate of 1.2 kg/s. The heating is to be com

bixtya [17]

Answer:L=109.16 m

Explanation:

Given

initial temperature $=20^{\circ}C$

Final Temperature $=80^{\circ}C$

mass flow rate of cold fluid $\dot{m_c}=1.2 kg/s$

Initial Geothermal water temperature $T_h_i=160^{\circ}C$

Let final Temperature be T

mass flow rate of geothermal water $\dot{m_h}=2 kg/s$

diameter of inner wall $d_i=1.5 cm$

$U_{overall}=640 W/m^2K$

specific heat of water $c=4.18 kJ/kg-K$

balancing energy

Heat lost by hot fluid=heat gained by cold Fluid

$\dot{m_c}c(T_h_i-T_h_e)= \dot{m_h}c(80-20)$

$2\times (160-T)=1.2\times (80-20)$

$160-T=36$

$T=124^{\circ}C$

As heat exchanger is counter flow therefore

$\Delta T_1=160-80=80^{\circ}C$

$\Delta T_2=124-20=104^{\circ}C$

$LMTD=\frac{\Delta T_1-\Delta T_2}{\ln (\frac{\Delta T_1}{\Delta T_2})}$

$LMTD=\frac{80-104}{\ln \frac{80}{104}}$

$LMTD=91.49^{\circ}C$

heat lost or gain by Fluid is equal to heat transfer in the heat exchanger

$\dot{m_c}c(80-20)=U\cdot A\cdot$ (LMTD)

$A=\frac{1.2\times 4.184\times 1000\times 60}{640\times 91.49}=5.144 m^2$

$A=\pi DL=5.144$

$L=\frac{5.144}{\pi \times 0.015}$

$L=109.16 m$

6 0

3 years ago

Ball a of mass 5.0 kilograms moving at 20 meters per second collides with ball b of unknown mass moving at 10 meters per second

RUDIKE [14]

M = mass of the ball A = 5.0 kg

m = mass of the ball B = ?

V = initial velocity of the ball A before collision = 20 m/s

v = initial velocity of the ball B before collision = 10 m/s

V' = final velocity of the ball A after collision = 10 m/s

v' = final velocity of the ball B after collision = 15 m/s

using conservation of momentum

M V + m v = M V' + m v'

(5.0) (20) + m (10) = (5.0) (10) + m (15)

100 + 10 m= 50 + 15 m

5 m = 50

m= 10 m/s

4 0

3 years ago