I think it’s Malleability
These 255.75 Hz and 256.25 Hz sounds can be thought of as a sum of two waves with frequencies.
Answer: Option A
<u>Explanation:</u>
To solve this, it is necessary to take into account the concepts related to frequency and period, and how they are related to each other.
Let frequency of beat = f
The relationship that defines both agreements is given by the equation,

Then the frequency for the previous period given (2sec) is

The beat frequency of two frequencies is equal to the difference between the two frequencies, then


Hence, Option A is correct.
Similarly we can check like these for other options too as below,
For option B,
.
For Option C, 
For Option D, 
For Option E, 
Therefore, the sum of the frequencies in the sound wave would be 256.25Hz and 255.75Hz.
Answer:
Explanation:
Force on the electron = q ( v x B )
q = - 1.6 x 10⁻¹⁹
v = (5.9i−6.4j)×10⁴
B = (−0.63i+0.65j)
v x B = (5.9i−6.4j)×10⁴ x (−0.63i+0.65j)
= (3.835 - 4.032 ) x 10⁴ k
= - 1970 k
Force on the electron = q ( v x B )
= - 1.6 x 10⁻¹⁹ x -1970 k
= 3.152 x 10⁻¹⁶ k
z-component of the force on the electron
Fz = 3.152 x 10⁻¹⁶ N
Answer:

Explanation:
We are given that
The wavelength of sound wave=
1 cm/s=
Speed of sound wave,v=
We have to find the period of the wave.
We know that
Frequency=
Using the formula
Frequency =
Hz
Time period=
Using identity:
Hence, the time period of the wave=