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oee [108]
2 years ago
6

Use the concepts on which maxwell’s equations are based to explain why a compass needle is deflected when the compass is brought

near a wire that is carrying an electric current.
Physics
1 answer:
miv72 [106K]2 years ago
7 0

A conductor that is conducting current generates a magnetic field everywhere around it. This magnetic field exerts force on the compass's magnetic needle, causing the needle to deviate.

Definition of Maxwell's rule

A current-conducting conductor creates a magnetic field everywhere around it. The magnetic needle of the compass experiences force from this magnetic field, which causes the needle to veer.

Equation for deflection

We have so far established that the total flux of electric field out of a closed surface is just the total enclosed charge multiplied by 1/ε0, ∫→E⋅d→A=q/ε0. This is Maxwell's first equation. It represents completely covering the surface with a large number of tiny patches having areas d→A.

To learn more about magnetic field refer : brainly.com/question/24761394

#SPJ4

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I think it’s Malleability
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3 years ago
Kwanzaa farts apple juice
8_murik_8 [283]

Answer:

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3 years ago
You hear a sound with a frequency of 256 Hz. The amplitude of the sound increases and decreases periodically: It takes 2 seconds
Fiesta28 [93]

These 255.75 Hz and 256.25 Hz sounds can be thought of as a sum of two waves with frequencies.

Answer: Option A

<u>Explanation:</u>

To solve this, it is necessary to take into account the concepts related to frequency and period, and how they are related to each other.

Let frequency of beat = f

The relationship that defines both agreements is given by the equation,

                f=\frac{1}{T}

Then the frequency for the previous period given (2sec) is

               f=\frac{1}{2}=0.5

The beat frequency of two frequencies is equal to the difference between the two frequencies, then

               f=\left|f_{1}-f_{2}\right|

               f=|255.75-256.25|=0.5 H z

Hence, Option A is correct.

Similarly we can check like these for other options too as below,

For option B, f=|255.5-256.5|=1 Hz.

For Option C, f=|255-257|=2 H z

For Option D, f=|254-258|=4 H z

For Option E, f=|256-2|=254 H z

Therefore, the sum of the frequencies in the sound wave would be 256.25Hz and 255.75Hz.

8 0
3 years ago
An electron moves with velocity v⃗ =(5.9i−6.4j)×104m/s in a magnetic field B⃗ =(−0.63i+0.65j)T. Determine the z-component of the
HACTEHA [7]

Answer:

Explanation:

Force on the electron = q ( v x B )

q = - 1.6 x 10⁻¹⁹

v = (5.9i−6.4j)×10⁴

B = (−0.63i+0.65j)

v x B = (5.9i−6.4j)×10⁴  x (−0.63i+0.65j)

= (3.835  - 4.032 ) x 10⁴ k

= - 1970 k

Force on the electron = q ( v x B )

= - 1.6 x 10⁻¹⁹ x -1970 k

= 3.152 x 10⁻¹⁶ k

z-component of the force on the electron

Fz = 3.152 x 10⁻¹⁶ N  

7 0
3 years ago
To navigate, a porpoise emits a sound wave that has a wavelength of 3.3 cm. The speed at which the wave travels in seawater is 1
dedylja [7]

Answer:

2.2\times 10^{-5} s

Explanation:

We are given that  

The wavelength of sound wave=\lambda=3.3 cm=3.3\times 10^{-2}m/s

1 cm/s=10^{-2}m/s

Speed of sound wave,v=1522 m/s

We have to find the period of the wave.

We know that

Frequency=\nu=\frac{v}{\lambda}

Using the formula

Frequency =\frac{1522}{3.3\times 10^{-2}}=4.6\times 10^{4} Hz

Time period=\frac{1}{4.6\times 10^4}=0.22\times 10^{-4}\times \frac{10}{10^1}=2.2\times 10^{-4-1}=2.2\times 10^{-5}s

Using identity:\frac{a^x}{a^y}=a^{x-y}

Hence, the time period of the wave=2.2\times 10^{-5} s

4 0
3 years ago
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