Molarity is equal to the moles of solute over liters of
solvent. In getting the molarity of HCl, you must know the formula for two
solutions which is equal to M1V1 = M2V2. (2.00 M HCl)V1
= (20.0 milliliters) (1.00
M NaOH) and you have the volume of 10
millimeters of HCl.
Answer:
P(O₂) = 287.41 mmHg
P(O₂) = 413.59 mmHg
Explanation:
Given data:
Total pressure = 701 mmHg
Mass of methane = 2.75 g
Mass of oxygen = 3.45 g
Partial pressure of each gas = ?
Solution:
Number of moles of methane:
Number of moles = mass/molar mass
Number of moles = 2.75 g/ 16 g/mol
Number of moles = 0.17 mol
Number of moles of oxygen:
Number of moles = mass/molar mass
Number of moles = 3.45 g/ 32 g/mol
Number of moles = 0.12 mol
Total number of moles = 0.12 mol + 0.17 mol = 0.29 mol
Partial pressure of oxygen:
P(O₂) = [ moles of oxygen / total moles ] × total pressure
P(O₂) = [0.12 / 0.29 ] × 701 mmHg
P(O₂) = 0.41 × 701 mmHg
P(O₂) = 287.41 mmHg
Partial pressure of methane:
P(O₂) = [ moles of oxygen / total moles ] × total pressure
P(O₂) = [0.17 / 0.29 ] × 701 mmHg
P(O₂) = 0.59 × 701 mmHg
P(O₂) = 413.59 mmHg
Answer:
7.5 G of copper oxide was reduced by heating of current of hydrogen and the weight of copper that remained was 6.35 gram in another experiment 19.05g of copper was dissolved in nitric acid and the resulting copper nitrate is converted into corporate oxide and the weight of copper oxide form was 23.35 gram show that these data are in accordance with the law of constant composition
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