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Zepler [3.9K]
3 years ago
8

A 750.0 mL solution contains 5.00 g of NaOH. If the molar mass of NaOH is 39.9969 g/mol, what is the molarity of the solution? (

3 points)
25 M N OH
0.167 M N OH
5,98 M N OH
O 0,0891 M NaOH

help please
Chemistry
1 answer:
Ghella [55]3 years ago
8 0

Answer:

0.167 M NaOH

Explanation:

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Calculate the number of grams of solute in 500.0 mL of 0.189 M KOH.
KIM [24]

Answer : The number of grams of solute in 500.0 mL of 0.189 M KOH is, 5.292 grams

Solution : Given,

Volume of solution = 500 ml

Molarity of KOH solution = 0.189 M

Molar mass of KOH = 56 g/mole

Formula used :

Molarity=\frac{\text{Mass of KOH}\times 1000}{\text{Molar mass of KOH}\times \text{Volume of solution in ml}}

Now put all the given values in this formula, we get the mass of solute KOH.

0.189M=\frac{\text{Mass of KOH}\times 1000}{(56g/mole)\times (500ml)}

\text{Mass of KOH}=5.292g

Therefore, the number of grams of solute in 500.0 mL of 0.189 M KOH is, 5.292 grams

7 0
3 years ago
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What are the factors why manila is the hottest place?
sveticcg [70]
because it is mostly sunny there
6 0
3 years ago
How much energy is required to raise the temperature of a 300.0
Montano1993 [528]

Answer:

Q = 1455.12 Joules.

Explanation:

Given the following data;

Mass = 300 grams

Initial temperature = 22.3

Final temperature = 59.9°C

Specific heat capacity = 0.129 J/gºC.

To find the quantity of energy;

Q = mcdt

Where,

Q represents the heat capacity.

m represents the mass of an object.

c represents the specific heat capacity of water.

dt represents the change in temperature.

dt represents the change in temperature.

dt = T2 - T1

dt = 59.9 - 22.3

dt = 37.6°C

Substituting the values into the equation, we have;

Q = 300*0.129*37.6

Q = 1455.12 Joules.

8 0
3 years ago
If 20 grams of Zinc phosphate reacts with excess hydrochloric acid and produces 18 grams of Zinc chloride what is the percent yi
fenix001 [56]

Answer:

Y=85\%

Explanation:

Hello!

In this case, since we know the balanced chemical reaction, we are first able to realize there is a 1:3 mole ratio between zinc phosphate and zinc chloride; it means that we can first compute the moles of the desired product via stoichiometry:

n_{ZnCl_2}=20gZn_3(PO_4)_2*\frac{1molZn_3(PO_4)_2}{386.11gZn_3(PO_4)_2}*\frac{3molZnCl_2}{1molZn_3(PO_4)_2}=0.16gZnCl_2

Next, since those moles are associated with the theoretical yield of zinc chloride, we obtain the corresponding mass:

m_{ZnCl_2}^{theoretical}=0.16molZnCl_2*\frac{136.29gZnCl_2}{1molZnCl_2} =21gZnCl_2

Finally, we compute the percent yield by diving the actual yield (18 g) by the theoretical yield:

Y=\frac{18g}{21g}*100\%\\\\Y=85\%

Best regards!

4 0
3 years ago
In the chemical equation: NO(g) + ½Cl2(g) → NOCl(g) How many moles of NOCl(g) are in the balanced chemical equation? fill in bla
Mrrafil [7]

Answer:

1

Explanation:

The numbers in front of the formulas (the coefficients) tell you how many moles of a substance are involved in a reaction.

If no coefficient is shown, we assume it is 1.

NOCl has no coefficient, so 1 mol of NOCl is in the balanced equation.

4 0
3 years ago
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