<span>The law of conservation of mass states that, "Mass can neither be created nor destroyed, only its form changes with respect to different forms of energy."
In any reaction, say 10 gms of water is decomposed into its constituents Hydrogen and Oxygen. But the mass remains conserved for the reaction. Although mass and energy are inter-convertible. But,the net mass/energy remains conserved i.e. the mass of products will be equal to the mass of reactants. </span>
Answer:
-41. 47
Explanation:
m = q / Cp x T
m = Mass
q = Energy (or joules)
Cp = Heat Capacity
T = Change in Temperature
Water's heat capacity is always 4.18.
This is the formula you'll need for change in temperature:
Final - Initial
So, 33 - 78 = -45
m = 7800 / 4.18 x -45
= -41.47
The percent by weight (w/w%) of sugar in soda : 6.216%
<h3>Further explanation</h3>
Given
mass of sugar = 23 g
total mass = 370 g
Required
the percent weight
Solution
%weight = (mass of solute : mass of solution) x 100%
solute = sugar
solution = solvent + solute = water + sugar
percent weight of sugar in soda :
= (23 : 370) x 100%
= 6.216 %
Answer:
The 
expression for the weak base equilibrium is:
![K_b=\frac{[(CH_3)_3NH^+][OH^-]}{[(CH_3)_3N]}](https://tex.z-dn.net/?f=K_b%3D%5Cfrac%7B%5B%28CH_3%29_3NH%5E%2B%5D%5BOH%5E-%5D%7D%7B%5B%28CH_3%29_3N%5D%7D)
Explanation:
The expression of the equilibrium constant of base 
can be given as:
![K_c=\frac{[(CH_3)_3NH^+][OH^-]}{[(CH_3)_3N][H_2O]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5B%28CH_3%29_3NH%5E%2B%5D%5BOH%5E-%5D%7D%7B%5B%28CH_3%29_3N%5D%5BH_2O%5D%7D)
]![K_b=K_c\times [H_2O]=\frac{[(CH_3)_3NH^+][OH^-]}{[(CH_3)_3N]}](https://tex.z-dn.net/?f=K_b%3DK_c%5Ctimes%20%5BH_2O%5D%3D%5Cfrac%7B%5B%28CH_3%29_3NH%5E%2B%5D%5BOH%5E-%5D%7D%7B%5B%28CH_3%29_3N%5D%7D)
As we know, water is pure solvent, we can put ![[H_2O]=1](https://tex.z-dn.net/?f=%5BH_2O%5D%3D1)
![K_b=K_c\times 1=\frac{[(CH_3)_3NH^+][OH^-]}{[(CH_3)_3N]}](https://tex.z-dn.net/?f=K_b%3DK_c%5Ctimes%201%3D%5Cfrac%7B%5B%28CH_3%29_3NH%5E%2B%5D%5BOH%5E-%5D%7D%7B%5B%28CH_3%29_3N%5D%7D)
So, the the expression for the weak base equilibrium is:
As far as I remember, the needed formula for squaric acid is C4H2O4.
According to this one mole should be 114.06 g., which means we have <span>0.015mol of this acid.
Then we can easly calculate : </span><span>4(0.015) = 0.06 mol for both for Carbon and Oxygen and </span><span>0.03 mol of Hydrogen.
</span><span>To get more clear answer, we multiply by avogadros :
</span><span>6.022 x 10^23. Hope everything is clear! regards</span>
