Answer:
M KIO3 = 1.254 mol/L
Explanation:
∴ w KIO3 = 553 g
∴ mm KIO3 = 214.001 g/mol
∴ volumen sln = 2.10 L
⇒ mol KIO3 = (553 g)×(mol/210.001 g) = 2.633 mol
⇒ M KIO3 = (2.633 mol KIO3 / (2.10 L sln)
⇒ M KIO3 = 1.254 mol/L
Answer:
131.8 g.
Explanation:
- There is a relation that relates the density of the substance (d) to the mass (m) and the volume of the substance (V):
<u><em>d = m / V.</em></u>
d = 0.8787 g/ml.
V = 0.15 L x 1000 = 150 ml.
- ∴ the mass of 0.15 L of benzene = d x V = (0.8787 g/ml) (150 ml) = 131.8 g.
<span>the atom that has these characteritics is called beryllium nucleus</span>
I think this is what you wanted, so good luck!
Like this? 234+34.1= 268.1 then round. If it is less than 5 then you round down if it is more then you round up. Because it is less the final number would be 268.1=268
