You can sole it because I believe in you
Answer:
<h2><em><u>Option</u></em><em><u> </u></em><em><u>B</u></em><em><u>:</u></em></h2><h2>
</h2>
Step-by-step explanation:
<em><u>Given</u></em><em><u>,</u></em>
Number of numbers of each side of the cube
= 4, 5, 6, 7, 8 and 9
= 6 numbers
Number of sides of cube having the number 5
= 1
<em><u>Therefore</u></em><em><u>,</u></em><em><u> </u></em>
Probability of getting a side of the cube of no. 5 is
Answer: C. 10x-3
Step-by-step explanation: I got this question correct on Edmentum.
Answer: y-value of the vertex of a ∪-shaped (positive) parabola
<u>Step-by-step explanation:</u>
For a quadratic: it is the y-value of the vertex of a positive parabola.
<em>If it is a negative parabola ( ∩-shaped), it is the maximum.</em>
For a cubic: it is the y-value of all of the vertices of the ∪-shaped sections of the graph. These are typically referred to as the "relative minima" when given an interval.
Answer:
probability of a crash with at least one fatality if a driver drives while legally intoxicated (BAC greater than 0.09) = 0.001932
Step-by-step explanation:
P(BAC=0|Crash with fatality)=0.625
P(BAC is between .01 and .09|Crash with fatality)=0.302
P(BAC is greater than .09|Crash with fatality)=0.069
Let the event of BAC = 0 be X
Let the event of BAC between 0.01 and 0.09 be Y
Let the event of BAC greater than 0.09 be Z
Let the event of a crash with at least one fatality = C
P(X|C) = 0.625
P(Y|C) = 0.302
P(Z|C) = 0.069
P(C) = 0.028
probability of a crash with at least one fatality if a driver drives while legally intoxicated (BAC greater than 0.09) = P(C n Z)
But note that the conditional probability of probability that a driver is intoxicated (BAC greater than 0.09) given that there was a crash that involved at least a fatality is given by
P(Z|C) = P(Z n C)/P(C)
P(Z n C) = P(Z|C) × P(C) = 0.069 × 0.028 = 0.001932
Hope this Helps!!!
