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tatyana61 [14]
3 years ago
12

If Natalie walked 3/5 in 1/2 hour, how fast did she walk, in miles per hour?

Mathematics
1 answer:
melisa1 [442]3 years ago
6 0
She walked .6 mph because 3/5 x 2= 6/10
1/2 x 2=1

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The length of the base of an isosceles triangle is x. The length of a leg is 2x-6. The perimeter of the triangle is 38. Find X
Norma-Jean [14]

Answer:

x = 10

Step-by-step explanation:

Perimeter of a triangle = the sum of the three sides.    

In an isosceles the legs are equal (2x - 6) and the base is x

Perimeter = (x) + (2x - 6) + (2x - 6)

          38  = 5x - 12

        38 + 12 = 5x

            50 =   5x

              \frac{50}{5} = \frac{5x}{5}

               10 = x

   

8 0
2 years ago
In the picture below, ABCD is a rectangle. If the area of triangle ABE is 40, what is the area of the triangle?
MariettaO [177]

Area of the rectangle: 112

Step-by-step explanation:

Picture is missing: find it in attachment.

The area of a triangle is given by

A=\frac{1}{2}bh

where

b is the length of the base

h is the height

For triangle ABE, we know that

A = 40 (area)

h = 8 (height)

So we can find the length of the base AE:

AE=b=\frac{2A}{h}=\frac{2(40)}{8}=10

Now we observe that the base of the rectangle, AD, is the sum of AE and DE, therefore:

AD=AE+DE=10+4=14

We also know the height of the rectangle AB is 8, and that the area of a rectangle is

A=bh

where b is the base and h the height. Therefore, the area of this rectangle is

A=bh=(AD)(AB)=(14)(8)=112

Learn more about area of figures:

brainly.com/question/4599754

brainly.com/question/3456442

brainly.com/question/6564657

#LearnwithBrainly

7 0
3 years ago
I need help very important
siniylev [52]

Answer:

∠ EFG = 83°, ∠ GCE = 97°

Step-by-step explanation:

Since FE and FG are tangents to the circle then

∠ FGC and ∠ FEC are right angles

The sum of the angles in quadrilateral CEFG = 360°

Sum the 4 angles and equate to 360

3x + 11 + 90 + 5x - 23 + 90 = 360, that is

8x + 168 = 360 ( subtract 168 from both sides )

8x = 192 ( divide both sides by 8 )

x = 24

Thus

∠ EFG = 3x + 11 = 3(24) + 11 = 72 + 11 = 83°

∠ GCE = 5x - 23 = 5(24) - 23 = 120 - 23 = 97°

4 0
3 years ago
How can the Pythagorean Identity be used to find sin θ, cos θ, or tan θ and the quadrant location of the angle?
Archy [21]

First lets see the pythagorean identities

sin^2 \Theta + cos^2 \Theta =1

So if we have to solve for sin theta , first we move cos theta to left side and then take square root to both sides, that is

sin^2 \Theta = 1-cos^2 \Theta => sin \theta = \pm \sqrt{1-cos^2 \Theta}

Now we need to check the sign of sin theta

First we have to remember the sign of sin, cos , tan in the quadrants. In first quadrant , all are positive. In second quadrant, only sin and cosine are positive. In third quadrant , only tan and cot are positive and in the last quadrant , only cos and sec are positive.

So if theta is in second quadrant, then we have to positive sign but if theta is in third or fourth quadrant, then we have to use negative sign .

5 0
2 years ago
Which quadratic relation has a y-intercept of 8?
Tpy6a [65]

Answer:

y = 0.5 (x^2 -2x + 16) has a y-intercept of 8.

Step-by-step explanation:

The x-coordinate of every y-intercept is zero.  To determine which of the four quadratics given here has a y-intercept of 8, we need only substitute 0 for x in each; if the result is 8, we've found the desired quadratic.

O y = 0.5(x + 2)(x + 4) becomes y = 0.5(2)(4) = 4 (reject this answer)

O y = 0.5 (x - 2)(x + 8) becomes y = 0.5(-2)(8) = -8 (reject)

O y = 0.5(x2 -2x - 16) becomes y = 0.5(-16) = -8 (reject)

<em>O y = 0.5 (x2 -2x + 16) becomes y = 0.5(16) = 8 This is correct; that '8' represents the y-intercept (0, 8).</em>

6 0
2 years ago
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