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Ilya [14]
3 years ago
15

152 + (-20) + 84 = The answers are 216, 48, -48, -126

Mathematics
2 answers:
andrey2020 [161]3 years ago
3 0

Answer:

216

Step-by-step explanation:

hope this was helpful.

Elanso [62]3 years ago
3 0

Answer:

216

Step-by-step explanation:

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Which multiplication expression is equal to 2 ÷ 1
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4 0
2 years ago
Margo sold 3 times as many pears as apples in a week. She sold 3,456 apples and pears. How many pears did she sell? Use a letter
klasskru [66]

She sold 2592 pears. If 2592/3=864 then when the total of pears and apples are added it should equal 3,456

2592+864=3456

7 0
3 years ago
Read 2 more answers
D^2(y)/(dx^2)-16*k*y=9.6e^(4x) + 30e^x
MA_775_DIABLO [31]
The solution depends on the value of k. To make things simple, assume k>0. The homogeneous part of the equation is

\dfrac{\mathrm d^2y}{\mathrm dx^2}-16ky=0

and has characteristic equation

r^2-16k=0\implies r=\pm4\sqrt k

which admits the characteristic solution y_c=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}.

For the solution to the nonhomogeneous equation, a reasonable guess for the particular solution might be y_p=ae^{4x}+be^x. Then

\dfrac{\mathrm d^2y_p}{\mathrm dx^2}=16ae^{4x}+be^x

So you have

16ae^{4x}+be^x-16k(ae^{4x}+be^x)=9.6e^{4x}+30e^x
(16a-16ka)e^{4x}+(b-16kb)e^x=9.6e^{4x}+30e^x

This means

16a(1-k)=9.6\implies a=\dfrac3{5(1-k)}
b(1-16k)=30\implies b=\dfrac{30}{1-16k}

and so the general solution would be

y=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}+\dfrac3{5(1-k)}e^{4x}+\dfrac{30}{1-16k}e^x
8 0
3 years ago
Let f(x)=x+3 and g(x)=1/x. The graph of (f*g)(x) is shown below.
Vlad [161]
For this case we have the following functions:
 f (x) = x + 3

g (x) = 1 / x When composing the functions we have:
 (fog) (x) = f (g (x))

 Substituting values we have:
 (fog) (x) = ((1 / x) +3)

 Rewriting:
 (fog) (x) = 1 / x + 3

 The function has a horizontal asymptote at y = 3.
 Therefore, the range of the function is all reals minus y = 3.
 Answer:
 
option 3
3 0
3 years ago
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