photo math duhhhhhhhhhhhhhhhhhhhh
Step-by-step explanation:
The initial image of the photo is 2 in by 4 in. The mat is 4 in by 6 in.
The new image is dilated by a scale of 2. So we double the dimensions. The new photo is 4 in by 8 in. The new mat is 8 in by 12 in.
Answer:
Cost of a coffee is <u>$2.5</u> and cost of a latte is <u>$4.25.</u>
Step-by-step explanation:
Let cost of 1 coffee be 'c' and cost of 1 latte be 'l' dollars.
Given:
4 coffees and 12 lattes cost $61.
12 coffees and 7 lattes cost $59.75.
∵ 1 coffee cost = 
∴ 4 coffees cost =
and 12 coffee cost = 
∵ 1 latte cost = 
∴ 12 lattes cost =
and 7 lattes cost = 
Now, as per question:

Now, multiplying equation (1) by -3 and adding the result to equation (2). This gives,

Now, plug in the value of 'l' in equation 1 to solve for 'c'. This gives,

Therefore, cost of a coffee is $2.5 and cost of a latte is $4.25.
Answer: The loser's card shows 6.
Explanation: Let's start by naming the first student A and the second student B.
Since the product of A and B are either 12, 15, or 18, let's list every single possibility, the first number being A's number and the second number being B's number.
1 12
1 15
1 18
2 6
2 9
3 4
3 5
3 6
4 3
5 3
6 2
6 3
9 2
12 1
15 1
18 1
Now, the information says that A doesn't know what B has, so we can immediately cross off all of the combinations that have the integer appearing once and once ONLY off, because if it happened once only, A would know of it straight away. Now, our sample space becomes much smaller.
1 12
1 15
1 18
2 6
2 9
3 4
3 5
3 6
6 2
6 3
Using this same logic, we know that we can cross off all of the digits that occur only once in B's column.
2 6
3 6
Now, A definitely knows what number B has because there is only one number left in B. Hence, we can conclude that the loser, B, has the integer 6.