What is the slope of the line perpendicular to a line that contains the points (-5,4) and (-2,4)

Mathematics

1 answer:

steposvetlana [31]3 years ago

7 0

Answer:

the slope of the line is: 0

Step-by-step explanation:

4-4=0

-2-5= 3

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Write an equation in whatever form you choose with the given characteristics Parallel to y = 3/5x - 8 and passes through (0, -3)

Alona [7]

Answer (this one's written in slope-intercept form):

$y= \frac{3}{5}x -3$

Step-by-step explanation:

1) Lines that are parallel to each other have the same slope. The line $y=\frac{3}{5} x-8$ is in slope intercept form, or $y = mx + b$ form, and the number in place of $m$ represents the slope. Knowing this, it looks like $\frac{3}{5}$ is in the place of the $m$ in that equation, so $\frac{3}{5}$ is the slope - and the slope we need to use for the answer, too.

2) Once you know a point that the line must pass through and a slope, you can write an equation with point-slope form, or $y-y_1 = m (x - x_1)$ . $m$ is the slope and $x_1$ and $y_1$ are the x and y values of the point it must pass through. So, substitute $\frac{3}{5}$ for $m$ , 0 for $x_1$ , and -3 for $y_1$ . Simplify and isolate y to put it in slope-intercept form: