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finlep [7]
3 years ago
10

What is the slope of the line perpendicular to a line that contains the points (-5,4) and (-2,4)

Mathematics
1 answer:
steposvetlana [31]3 years ago
7 0

Answer:

the slope of the line is: 0

Step-by-step explanation:

4-4=0

-2-5= 3

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X^2+17x=-42 <br> how do i find the solutions to this problem?
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photo math duhhhhhhhhhhhhhhhhhhhh

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Marissa has a photograph that measures 2 in. by 4 in. She has mounted the picture on a mat so that there is a border that measur
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Step-by-step explanation:

The initial image of the photo is 2 in by 4 in.  The mat is 4 in by 6 in.

The new image is dilated by a scale of 2.  So we double the dimensions.  The new photo is 4 in by 8 in.  The new mat is 8 in by 12 in.

7 0
3 years ago
What value(s) of x will make each equation below true?
kvasek [131]

Answer:

a X=0

b X=0

c X= undetermined

5 0
2 years ago
Read 2 more answers
4 coffees and 12 lattes. Costs $61
Gala2k [10]

Answer:

Cost of a coffee is <u>$2.5</u> and cost of a latte is <u>$4.25.</u>

Step-by-step explanation:

Let cost of 1 coffee be 'c' and cost of 1 latte be 'l' dollars.

Given:

4 coffees and 12 lattes cost $61.

12 coffees and 7 lattes cost $59.75.

∵ 1 coffee cost = c

∴ 4 coffees cost = 4c and 12 coffee cost = 12c

∵ 1 latte cost = l

∴ 12 lattes cost = 12l and 7 lattes cost = 7l

Now, as per question:

4c+12l=61-----1\\12c+7l=59.75----2

Now, multiplying equation (1) by -3 and adding the result to equation (2). This gives,

-3(4c+12l)=-3(61)\\\\-12c-36l=-183\\12c+7l=59.75\\+\\----------\\0-29l=-123.25\\\\l=\frac{-123.25}{-29}=\$4.25

Now, plug in the value of 'l' in equation 1 to solve for 'c'. This gives,

4c+12(4.25)=61\\\\4c+51=61\\\\4c=61-51\\\\4c=10\\\\c=\frac{10}{4}=\$2.5

Therefore, cost of a coffee is $2.5 and cost of a latte is $4.25.

4 0
3 years ago
Two intelligent, honest students are sitting together at lunch one day when their math teacher hands them each a card. “your car
Lady bird [3.3K]
Answer: The loser's card shows 6.

Explanation: Let's start by naming the first student A and the second student B.
Since the product of A and B are either 12, 15, or 18, let's list every single possibility, the first number being A's number and the second number being B's number.

1     12
1     15
1     18
2     6
2     9
3     4
3     5
3     6
4     3
5     3
6     2
6     3
9     2
12  1
15  1
18  1

Now, the information says that A doesn't know what B has, so we can immediately cross off all of the combinations that have the integer appearing once and once ONLY off, because if it happened once only, A would know of it straight away. Now, our sample space becomes much smaller.

1     12
1     15
1     18
2     6
2     9
3     4
3     5
3     6
6     2
6     3

Using this same logic, we know that we can cross off all of the digits that occur only once in B's column.

2     6
3     6

Now, A definitely knows what number B has because there is only one number left in B. Hence, we can conclude that the loser, B, has the integer 6.
4 0
3 years ago
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