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finlep [7]
3 years ago
10

What is the slope of the line perpendicular to a line that contains the points (-5,4) and (-2,4)

Mathematics
1 answer:
steposvetlana [31]3 years ago
7 0

Answer:

the slope of the line is: 0

Step-by-step explanation:

4-4=0

-2-5= 3

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Please help I don’t understand how to solve this !
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Answer:

x = 30

Step-by-step explanation:

x + 2x + 3x = 180

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              6       6

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8 0
3 years ago
What is the volume of a picnic cooler that it 2ft wide, 3ft long, and 1 1/2 ft deep? PLZ HELP
olga_2 [115]
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3 years ago
Write an absolute value equation that has the solutions x=8​ and x=18
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Answer:

|x-5|=13

Step-by-step explanation:

I think this is right

8 0
3 years ago
1. Part A: Use the properties of exponents to explain why 64^1/2 is called the square root of 64.
Dmitriy789 [7]
A: When you multiply two numbers, their exponents add. 
So, 64^{\frac{1}{2}} * 64^{\frac{1}{2}} = 64^{\frac{1}{2} + \frac{1}{2}} = 64^{1} = 64

Since 64^1/2 multiplied by itself is 64, then it is the square root of 64.

B: The area is irrational. 7 * √7 is irrational.
8 0
3 years ago
Read 2 more answers
A = 1011 + 337 + 337/2 +1011/10 + 337/5 + ... + 1/2021
egoroff_w [7]

The sum of the given series can be found by simplification of the number

of terms in the series.

  • A is approximately <u>2020.022</u>

Reasons:

The given sequence is presented as follows;

A = 1011 + 337 + 337/2 + 1011/10 + 337/5 + ... + 1/2021

Therefore;

  • \displaystyle A = \mathbf{1011 + \frac{1011}{3} + \frac{1011}{6} + \frac{1011}{10} + \frac{1011}{15} + ...+\frac{1}{2021}}

The n + 1 th term of the sequence, 1, 3, 6, 10, 15, ..., 2021 is given as follows;

  • \displaystyle a_{n+1} = \mathbf{\frac{n^2 + 3 \cdot n + 2}{2}}

Therefore, for the last term we have;

  • \displaystyle 2043231= \frac{n^2 + 3 \cdot n + 2}{2}

2 × 2043231 = n² + 3·n + 2

Which gives;

n² + 3·n + 2 - 2 × 2043231 = n² + 3·n - 4086460 = 0

Which gives, the number of terms, n = 2020

\displaystyle \frac{A}{2}  = \mathbf{ 1011 \cdot  \left(\frac{1}{2} +\frac{1}{6} + \frac{1}{12}+...+\frac{1}{4086460}  \right)}

\displaystyle \frac{A}{2}  = 1011 \cdot  \left(1 - \frac{1}{2} +\frac{1}{2} -  \frac{1}{3} + \frac{1}{3}- \frac{1}{4} +...+\frac{1}{2021}-\frac{1}{2022}  \right)

Which gives;

\displaystyle \frac{A}{2}  = 1011 \cdot  \left(1 - \frac{1}{2022}  \right)

\displaystyle  A = 2 \times 1011 \cdot  \left(1 - \frac{1}{2022}  \right) = \frac{1032231}{511} \approx \mathbf{2020.022}

  • A ≈ <u>2020.022</u>

Learn more about the sum of a series here:

brainly.com/question/190295

8 0
2 years ago
Read 2 more answers
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