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olga nikolaevna [1]
3 years ago
12

Alyssa took a math test with 20 questions and she answered 16 questions correctly. In order get an A she needs to answer at leas

t 90 percent of the questions correctly
Mathematics
1 answer:
Tatiana [17]3 years ago
5 0

Answer:

she got 80% . in order to get 90% she would have had to get 18 questions right

Step-by-step explanation:

20=100%

2=10%

2×9=90%

18=90%

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Multiply (a-b)(a^2+ab+b^2)​
AlexFokin [52]

Answer:

=(a-b)(a^2+ab+b^2)

= a^3+a^2b+ab+ab^2-ba^2-ab^2-b^3

SIMPLIFY

=a^3+ab-b^3

3 0
3 years ago
A graphic designer created a logo on 8 1/2 by 11 inch paper. In order to place on a business card the logo needs to be 1 7/10 in
neonofarm [45]
K  - scale factor
a = 8 1/2
b = 11
a₁ = 1 7/10
b₁ = 2 1/5


k = \frac{a_1}{a}=\frac{b_1}b\\\\\\\frac{a_1}{a}=\dfrac{1 \frac{7}{10}}{8\frac12}=1 \frac{7}{10}:8\frac12=\frac{17}{10}:\frac{17}2=\frac{17}{10}\cdot\frac2{17}=\frac15\cdot\frac11=\frac15\\\\\\\frac{b_1}{b}=\dfrac{2 \frac{1}{5}}{11}=2\frac15:11=\frac{11}{5}\cdot\frac1{11}=\frac15\cdot\frac11=\frac15 \\\\\\\frac{a_1}{a}=\frac{b_1}b=\frac15\ \ \ \implies\ \ \ k=\frac15
6 0
3 years ago
For what values of x is f(x) = |x + 1| differentiable? I'm struggling my butt off for this course
pav-90 [236]

By definition of absolute value, you have

f(x) = |x+1| = \begin{cases}x+1&\text{if }x+1\ge0 \\ -(x+1)&\text{if }x+1

or more simply,

f(x) = \begin{cases}x+1&\text{if }x\ge-1\\-x-1&\text{if }x

On their own, each piece is differentiable over their respective domains, except at the point where they split off.

For <em>x</em> > -1, we have

(<em>x</em> + 1)<em>'</em> = 1

while for <em>x</em> < -1,

(-<em>x</em> - 1)<em>'</em> = -1

More concisely,

f'(x) = \begin{cases}1&\text{if }x>-1\\-1&\text{if }x

Note the strict inequalities in the definition of <em>f '(x)</em>.

In order for <em>f(x)</em> to be differentiable at <em>x</em> = -1, the derivative <em>f '(x)</em> must be continuous at <em>x</em> = -1. But this is not the case, because the limits from either side of <em>x</em> = -1 for the derivative do not match:

\displaystyle \lim_{x\to-1^-}f'(x) = \lim_{x\to-1}(-1) = -1

\displaystyle \lim_{x\to-1^+}f'(x) = \lim_{x\to-1}1 = 1

All this to say that <em>f(x)</em> is differentiable everywhere on its domain, <em>except</em> at the point <em>x</em> = -1.

4 0
3 years ago
HELP ASAP Use the data below
beks73 [17]

Answer:

Part A:

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Step-by-step explanation:

Part B: IQR= 25

This shows that the data varies for 25 different numbers. That HALF of the data is between 25 numbers.

Part C: Using a box-and-whisker plot you can interpret the different values. Minimum is the first dot (10), connected to the first line (Q1 which is 17.5), connected by a box to the median (30), connected by a box to the third line (Q3 which is 42.5), connected to the last dot which is the maximum (50). And IQR is Q3-Q1, so 42.5-17.5 which is 25.

8 0
3 years ago
What is negative six one third equal negative nine three fourths
11Alexandr11 [23.1K]

Answer:

Do you have a picture of the problem so I can see it

8 0
3 years ago
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