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Mashcka [7]
3 years ago
6

9x5+5^5=8x7+5^6 what is the answer to this equation

Mathematics
2 answers:
antoniya [11.8K]3 years ago
7 0

Answer:

If the x is multiplication, then the statement is false. If the x is a variable, it is also false.

Step-by-step explanation:

ra1l [238]3 years ago
5 0
<h2>Answer:</h2>

<u>The answer is</u><u> 9x^5 - 8x^7 = 12500</u>

<h2>Step-by-step explanation:</h2>

See the attached image

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Which function is the inverse of function f? f(x)=9x^2-12
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Answer:

f−1(x)=√x+123,−√x+123

Step-by-step explanation:

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3 years ago
Pleaz Helpz!!! I needz this done before my final!!!
Marta_Voda [28]

the perimeter of the field is 442

width=w

the length of the field is 9 yards less than quadruple W

L=4x - 9

the perimeter is P=2L+2W

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P= 2(4w-9) + 2W

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Exit How many significant digits are in the number 0.00120?<br> a. 2<br> b. 3<br> c. 5<br> d. 6
grigory [225]
The answer
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8 0
3 years ago
Read 2 more answers
Verify that the following function is a probability mass function, and determine the requested probabilities. f left-parenthesis
Licemer1 [7]

Answer:

f(x) = \frac{27}{13} (\frac{1}{3})^x , x=1,2,3

1) f(x_i) \geq 0, \forall x_i

2) sum_{i=1}^n P(X_i) =1

We can find the individual probabilities and we got:

f(1)= \frac{27}{13} (\frac{1}{3})^1 =0.6923

f(2)= \frac{27}{13} (\frac{1}{3})^2 =0.2307

f(3)= \frac{27}{13} (\frac{1}{3})^3 =0.0770

And the sum of the 3 values 0.6923+0.2307+0.0770= 1 so then we satisfy all the conditions and we can conclude that f(x) is a probability distribution.

P(X \leq 1) = P(X=1) =0.6923

P(X>1) = P(X=2) +P(X=3) = 0.2307+0.0770=0.3077

P(2

Step-by-step explanation:

For this case we have the following density function:

f(x) = \frac{27}{13} (\frac{1}{3})^x , x=1,2,3

In order to satisfty that this function is a probability mass function we need to check two conditions:

1) f(x_i) \geq 0, \forall x_i

2) sum_{i=1}^n P(X_i) =1

We can find the individual probabilities and we got:

f(1)= \frac{27}{13} (\frac{1}{3})^1 =0.6923

f(2)= \frac{27}{13} (\frac{1}{3})^2 =0.2307

f(3)= \frac{27}{13} (\frac{1}{3})^3 =0.0770

And the sum of the 3 values 0.6923+0.2307+0.0770= 1 so then we satisfy all the conditions and we can conclude that f(x) is a probability distribution.

And if we want to find the following probabilities:

P(X \leq 1) = P(X=1) =0.6923

P(X>1) = P(X=2) +P(X=3) = 0.2307+0.0770=0.3077

P(2

7 0
3 years ago
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