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choli [55]
4 years ago
10

How does air pressure affect the boiling point of a liquid?

Chemistry
2 answers:
Alona [7]4 years ago
5 0

The answer is C. because As elevation increases, atmospheric pressure decreases because air is less dense at higher altitudes. Because the atmospheric pressure is lower, the vapor pressure of the liquid needs to be lower to reach boiling point. Therefore, less heat is required to make the vapor pressure equal to the atmospheric pressure.Apr 30, 2016

SCORPION-xisa [38]4 years ago
3 0

The answer is D. Air pressure keeps liquid molecules from escaping as a gas. I just took the test on APEX chemistry and i got it right

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A sports car and a fully loaded semi truck pull side by side at a red light. Using your knowledge of acceleration, predict which
Len [333]
According to Newtons second law of motion:

a =  \frac{F}{m}

This shows, acceleration and mass are inversely proportional. So, larger the mass, less will be the acceleration produced and vice versa.

In case of a sports car and a fully loaded truck, the mass of truck is a lot more than the sports car. As a result the sports car will accelerate faster when the traffic light turns green.
7 0
3 years ago
Solid calcium oxide reacts with sulfur trioxide gas to produce solid calcium sulfate
antiseptic1488 [7]

<u>Answer:</u> The chemical equation for the given reaction is given below.

<u>Explanation:</u>

When solid calcium oxide reacts with sulfur trioxide gas to produce solid calcium sulfate, the chemical equation follows:

CaO(s)+SO_3(g)\rightarrow CaSO_4(s)

This is the reaction when a metal oxide reacts with non-metal oxide to produce a salt.

By Stoichiometry of the reaction:

1 mole of solid calcium oxide reacts with 1 mole of sulfur trioxide gas to produce 1 mole of solid calcium sulfate.

5 0
3 years ago
What kinds of intermolecular forces are present in a mixture of ethanol (ch3ch2oh) and water?
Svetllana [295]
<h3><u>Answer;</u></h3>

Dipole-dipole and hydrogen bonding

<h3><u>Explanation;</u></h3>
  • <em><u>A solution of water and ethanol contains the dipole-dipole forces and hydrogen bonds as the intermolecular forces between molecules.</u></em>
  • <em><u>Hydrogen bonding is a type of interactions between molecules that occurs when a partially negative atom such as oxygen end of one of the molecules is attracted to a partially positive hydrogen end of another molecule.</u></em>
  • <em><u>Dipole-dipole forces</u></em> results from the unsymmetrical distribution of electrons, thus the polarity does not balance, thus resulting to a dipole attraction between molecules.
5 0
4 years ago
Read 2 more answers
A horse gallops along a racecourse at a speed of 40 km/h. It takes the horse 3 minutes to run the length of the track.
Natali [406]

To convert minutes to hours we divide the minutes by 60. So if we divide 3 by 60 we get 0.05 hours.

<h3>How to convert minutes into hour?</h3>

We know that in hour, there are 60 minutes so if we go from minutes to hours then we have to divide the number by 60 and when we go from hours to minutes we multiply with the same 60 number.

So we can conclude that to convert minutes to hours we divide the minutes by 60. So if we divide 3 by 60 we get 0.05 hours.

Learn more about hour here: brainly.com/question/291457

#SPJ1

7 0
2 years ago
Argon (Ar) and helium (He) are initially in separate compartments of a container at 25°C. The
love history [14]

Answer:

(a) V_B=11.68L

(b) x_{He}=0.533

Explanation:

Hello,

In this case, since the both gases behave ideally, with the given information we can compute the moles of He in A:

n_A=\frac{0.082\frac{atm*L}{mol*K}*298K}{1.974 atm*6.00L}=2.063mol

Thus, since the final pressure is 3.60 bar, we can write:

P=x_{Ar}P_A+x_{He}P_B\\\\P=\frac{n_{Ar}}{n_{Ar}+n_{He}} P_A+\frac{n_{He}}{n_{Ar}+n_{He}} P_B\\\\3.60bar=\frac{2.063mol}{2.063mol+n_{He}} *2.00bar+\frac{n_{He}}{2.063mol+n_{He}} *5.00bar

The moles of helium could be computed via solver as:

n_{He}=2.358mol

Or algebraically:

3.60bar=\frac{1}{2.063mol+n_{He}} *(4.0126+5.00*n_{He})\\\\7.314+3.60n_{He}=4.013+5.00*n_{He}\\\\7.314-4.013=5.00*n_{He}-3.60n_{He}\\\\n_{He}=\frac{3.3}{1.4}=2.358mol

In such a way, the volume of the compartment B is:

V_B=\frac{n_{He}RT}{P_B}=\frac{2.358mol*0.082\frac{atm*L}{mol*K}*298.15K}{4.935atm}\\  \\V_B=11.68L

Finally, he mole fraction of He is:

x_{He}=\frac{2.358}{2.358+2.063}\\ \\x_{He}=0.533

Regards.

8 0
3 years ago
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