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Mashcka [7]
3 years ago
5

EASYYYYYYYYYYY A batter hits two balls during practice. Ball A travels 10 meters, while ball B travels 12 meters. The batter dec

ides to hit ball A with less force. How will this change the motion of ball B?
The motion of ball B will increase.
The motion of ball B will decrease.
The motion of ball B will stay the same.
The motion of ball B will become the same as ball A.
Chemistry
2 answers:
Doss [256]3 years ago
5 0

Answer:

The motion of ball B will increase

Explanation:

Because if you hit ball A with less force than ball B then that means that ball B will go faster because you had hit ball A will less force witch will not be as faster as ball B.

Korolek [52]3 years ago
3 0

Answer:

The first one

Explanation:

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3 years ago
If cacl2 is dissolved in water, what can be said about the concentration of the ca2+ ion? view available hint(s) if is dissolved
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3 years ago
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What is the concentration (in M) of a 225ml potassium sulfate solution that contains 4.15g of potassium?
mars1129 [50]

The concentration of solution in M or mol/L can be calculated using the following formula:

C=\frac{n}{V} .... (1)

Here, n is number of moles and V is volume of solution in L.

The molecular formula of potassium sulfate is K_{2}SO_{4} thus, there are 2 moles of potassium in 1 mol of potassium sulfate.

1 mol of potassium will be there in 0.5 mol of potassium sulfate.

Mass of potassium is 4.15 g, molar mass is 39.1 g/mol.

Number of moles can be calculated as follows:

n=\frac{m}{M}

Here, m is mass and M is molar mass

Putting the values,

n=\frac{(4.15 g}{(39.1 g/mol}=0.1061 mol

Thus, number of moles of  K_{2}SO_{4} will be 0.1061\times 0.5=0.053 mol.

The volume of solution is 225 mL, converting this into L,

1 mL=10^{-3}L

Thus,

225 mL=0.225 L

Putting the values in equation (1),

C=\frac{(0.053 mol}{0.225 L}=0.236 M

Therefore, concentration of potassium sulfate solution is 0.236 M.


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3 years ago
Ayuda es urgente!! el tronco de madera y las cenizas pesan lo mismo ?​
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Answer:

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Explanation:

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