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STALIN [3.7K]
3 years ago
5

A small cube of iron and a large flat sheet of iron contain the same volume. Which one will completely rust first? Explain why.

Chemistry
1 answer:
allochka39001 [22]3 years ago
6 0
Flat as more oxygen and water can react over it think of it like this would a cube rust faster than a sheet
yiseli
2 years ago
Sample Response: The flat sheet will completely rust before the iron cube. Since they both have the same volume, the flat sheet has more surface area than the small cube. This means more particles are exposed on the flat sheet that can react in a chemical reaction
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3 years ago
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emmasim [6.3K]

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mmonium phosphate NH43PO4 is an important ingredient in many solid fertilizers. It can be made by reacting aqueous phosphoric ac
Paladinen [302]

Answer:

0.022 moles of ammonium phosphate produced by the reaction of 0.065mol of ammonia.

Explanation:

H_3PO_4+3NH_3\rightarrow (NH_4)_3PO_4

Moles of ammonia = 0.065 moles

According to reaction, 3 moles of ammonia gives 1 mole of ammonium phosphate ,then 0.065b moles of ammonia will give:

\frac{1}{3}\times 0.065 mol= 0.02166 mol\approx 0.022 mol

0.022 moles of ammonium phosphate produced by the reaction of 0.065mol of ammonia.

8 0
3 years ago
A gaseous mixture contains 434.0 Torr H 2 ( g ) , 434.0 Torr H2(g), 389.9 Torr N 2 ( g ) , 389.9 Torr N2(g), and 77.9 Torr Ar (
weqwewe [10]

Answer:

H₂: 0.48,  N₂: 0.43;  Ar: 0.09

Explanation:

First of all, sum all the pressures to know the total pressure in the mixture.

434 Torr + 389.9 Torr + 77.9 Torr = 901.8 Torr

Mole fraction = Pressure gas / Total Pressure

Mole Fraction H₂: 434 Torr /901.8 Torr = 0.48

Mole Fraction N₂: 389.9 /901.8 Torr =0.43

Mole Fraction Ar:  77.9 /901.8 Torr = 0.09

Remember: <u>SUM OF MOLE FRACTION = 1</u>

8 0
3 years ago
If the pressure exerted by a gas at 100 Celsius in a volume of 0.044 L is 3.81 atm, how many maples of gas are present
Vera_Pavlovna [14]

The number of moles of gas present are 0.0054

<u>Explanation:</u>

Given-

Temperature, T = 100°C = 100 + 273 = 373K

Volume, V = 0.044L

Pressure, P = 3.81 atm

Moles of gas, n = ?

We know,

PV = nRT

R = 0.082 L.atm.K⁻¹.mol⁻¹

n = PV/RT

n = (3.81)(0.044)/(0.082)(373)

n = 0.0054 moles

Therefore, number of moles of gas present are 0.0054

7 0
3 years ago
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