Question

PLEASE HELP!! WILL MARK BRAINLIEST!! TIME IS RUNNING OUT!!!

Answer 1

We can use the heat equation,
Q = mcΔT 

Where Q is the amount of energy transferred (J), m is the mass of the substance (kg), c is the specific heat (J g⁻¹ °C⁻¹) and ΔT is the temperature difference (°C).

 

According to the given data,

Q = 300 J 

m = 267 g

c = ?
ΔT = 12 °C

 

By applying the formula,

300 J = 267 g x c x 12 °C
       c = 0.0936 J g⁻¹ °C⁻¹

Hence, specific heat of the given substance is 0.0936 J g⁻¹ °C⁻¹.