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matrenka [14]
4 years ago
13

PLEASE HELP!! WILL MARK BRAINLIEST!! TIME IS RUNNING OUT!!!

Chemistry
1 answer:
Juli2301 [7.4K]4 years ago
6 0

<span>We can use the heat equation,
Q = mcΔT </span>

<span>

Where Q is the amount of energy transferred (J), m is the mass of the substance (kg), c is the specific heat (J g</span>⁻¹ °C⁻<span>¹) and ΔT is the temperature difference (°C).</span>

 

According to the given data,

Q = 300 J 

m = 267 g

<span> c = ?
ΔT = 12 °C</span>

 

By applying the formula,

<span>300 J = 267 g x c x 12 °C
       c = 0.0936 J g</span>⁻¹ °C⁻<span>¹

Hence, specific heat of the given substance is </span>0.0936 J g⁻¹ °C⁻¹.

 


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