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miss Akunina [59]
2 years ago
8

8 1/2 multiply 1 1/2

Mathematics
1 answer:
Korolek [52]2 years ago
8 0

Answer:

12.75 or 12\frac{3}{4}

Step-by-step explanation:

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Find the midpoint of the segment with the given endpoints (5,-9) and (-2,-2)
QveST [7]
Another way to solve this is to use the Midpoint Formula.  The midpoint of a segment joining points (x_1,y_1) and (x_2,y_2) is

\left(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} \right)

So the midpoint of your segment is

\left(\frac{5+(-2)}{2},\frac{-9+(-2)}{2}\right) = \left(\frac{3}{2},-\frac{11}{2} \right)

Perhaps it helps to see that the x-coordinate of the midpoint is just the average of the x-coordinates of the points.  Ditto for the y-coordinate of the midpoint; just average the y's.
6 0
3 years ago
What is mL BCD ?<br><br><br><br><br><br><br><br><br><br> THANK U &lt;3
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m∠BCD= m∠ACB ÷ 2 = 134.76° ÷ 2 = 67.38°

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7 0
2 years ago
Which expression is equivalent to 2(3g – 4) - (8g + 3)?
Brilliant_brown [7]

Answer:

The Answer is D

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
The area of sandbox in park is represented by 2X^2-5x-3 find the dimensions of the sandbox in terms of
lora16 [44]

Answer:

The dimension of the sandbox is (2x+1) by (x - 3)

Step-by-step explanation:

It seems the complete question will be:

The area of sandbox in park is represented by 2X^2-5x-3 find the dimensions of the sandbox in terms of x.

Step-by-step explanation:

From the question, the given expression is 2X^2-5x-3. This can be rewritten as

2x^{2} -5x-3

If the area of the sandbox in park is represented by this expression, then the dimensions of the sandbox will be the product of the factors. To determine the factors, we will factorize the given quadratic expression.

Factorizing the expression 2x^{2} -5x-3, we get

2x^{2} -6x+x-3

2x(x-3)+1(x-3)

(2x+1)(x-3)

Hence, the dimension of the sandbox is (2x+1) by (x - 3)

6 0
3 years ago
To simplify the following expression, which operation would you complete second?
Bingel [31]
Divide, the first operation is the parentheses and then division
3 0
2 years ago
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