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3 years ago

Is CuBr2 an ionic or covalent compound?

Chemistry

2 answers:

lidiya [134]3 years ago

7 0

Ionic compound because it consists of a metal and non metal, covalent compounds only consist of non metals

telo118 [61]3 years ago

4 0

Answer : The compound $CuBr_2$ is an ionic compound.

Explanation :

Ionic compound are the compounds where the atoms are bonded through ionic bond.

Ionic bonds are formed by the complete transfer of electrons. The atom which looses the electron is considered as electropositive atom and the atom which gains the electron is considered as electronegative atom.

The ionic bonds are formed between one metal and one non-metal.

Covalent compound are the compounds in which atoms are covalently bonded.

Covalent bonds are formed by the equal sharing of electrons. These bonds are commonly formed between two non-metals.

In the given compound $CuBr_2$ , copper (Cu) is a metal and bromine (Br) is a non-metal. So, $CuBr_2$ will form ionic bond.

Hence, the compound $CuBr_2$ is an ionic compound.

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Which of the following describes the difference between nitrogen-14 and nitrogen-15?

svetlana [45]

The atomic number of a neutral atom is equal to the number of protons and the number of electrons of the atom. The atomic weight meanwhile is equal to the sum of the number of protons and number of neutrons. nitrogen has 7 protons or electrons. hence nitrogen -14 has 7 neutrons while nitrogen -15 has 8 neutrons. answer is D

8 0

3 years ago

A transformer has a primary voltage of 115 V and a secondary voltage of 24 V. If the number of turns in the primary is 345, how

evablogger [386]

There are numerous information's of immense importance already given in the question.
Primary voltage of the transformer (V1) = 115 V
Secondary voltage of the transformer (V2) = 24 V
Number of turns in the primary (T1) = 345
Let us assume the number of turns in the secondary = T2
Then
(V1/V2) = (T1/T2)
(115/24) = 345/T2
115T2 = 345 * 24
115 T2 = 8280
T2 = 8280/115
= 72
So the correct option among all the options given in the question is option "C".

7 0

4 years ago

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xxMikexx [17]

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4 0

3 years ago

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Mumz [18]

Answer:

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8 0

3 years ago

Aqueous hydrochloric acid will react with solid sodium hydroxide to produce aqueous sodium chloride and liquid water . Suppose 1

blsea [12.9K]

Answer: The maximum amount of water that can be produced is 0.74 g

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Putting values in equation 1, we get:

$\text{Moles of hydrochloric acid:}=\frac{1.5g}{36.5g/mol}=0.041mol$

$\text{Moles of sodium hydroxide}=\frac{2.67g}{40g/mol}=0.067mol$

The chemical equation for the reaction is

$HCl+NaOH\rightarrow NaCl+H_2O$

By Stoichiometry of the reaction:

1 mole of HCl reacts with 1 mole of NaOH

So, 0.041 moles of HCl will react with = $\frac{1}{1}\times 0.041=0.041mol$ of NaOH

As, given amount of NaOH is more than the required amount. So, it is considered as an excess reagent. Thus, HCl is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 mole of HCl produces = 1 mole of water

So, 0.041 moles of HCl will produce = $\frac{1}{1}\times 0.041=0.041moles$ of water

Mass of water= $moles\times {\text{Molar Mass}}=0.041mol\times 18g/mol=0.74g$

Thus the maximum amount of water that can be produced is 0.74 g

3 0

3 years ago