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3 years ago

Thank you I will Mark brainlist solve for M 8m+95 < -87m + 5

Mathematics

1 answer:

posledela3 years ago

4 0

Answer:

The answer should be x < $\frac{-18}{19}$

Step-by-step explanation:

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Use a table of values with at least 5 values to graph the following function:

34kurt

The given expression :

$y=(\frac{1}{2})^x$

For coordinates:

put x = 0 then :

$\begin{gathered} y=(\frac{1}{2})^0 \\ y=1 \end{gathered}$

Coordinate : (x, y) = (0, 1)

Put x= 1 and simplify :

$\begin{gathered} y=(\frac{1}{2})^1 \\ y=\frac{1}{2} \\ y=0.5 \end{gathered}$

Coordinate : (x, y) = ( 1, 0.5)

Put x = (-2) and simplify :

$\begin{gathered} y=(\frac{1}{2})^{-2} \\ y=\frac{1^{-2}}{2^{-2}} \\ y=\frac{2^2}{1^2} \\ y=2^2 \\ y=4 \end{gathered}$

Coordinate : (x, y) = ( -2, 4)

Put x = (-3) and simplify :

$\begin{gathered} y=(\frac{1}{2})^{-3} \\ y=\frac{1^{-3}}{2^{-3}} \\ y=\frac{2^3}{1^3} \\ y=2^3 \\ y=8 \end{gathered}$

Coordinate : (x, y) = (-3, 8)

Substitute x = (-1) and simplify :

$\begin{gathered} y=(\frac{1}{2})^x \\ y=(\frac{1}{2})^{-1} \\ y=\frac{1^{-1}}{2^{-1}} \\ y=\frac{2}{1} \\ y=2 \end{gathered}$

Coordinate : (x, y) = ( -1, 2)

So, the coordinates are :

The graph is :

4 0

1 year ago

Santa Claus can buy 3 reindeer and a sleigh for $800. If the sleigh cost $230, how much did each reindeer cost? Define the varia

nydimaria [60]

Answer:

$190

Step-by-step explanation:

800-230=570

570÷3=190

8 0

3 years ago

Question 5 (1 point)

Damm [24]

Answer:

36 and 49

Step-by-step explanation:

Please mark me as brainlyest

5 0

2 years ago

⅒ (to decimal)<br><br>A. 0.1<br>B. 0.53<br>C. 0.10

nydimaria [60]

⅒ (to decimal)

A. 0.1

7 0

2 years ago

Using properties of sets show that : a) A ∩ (A’ U B) = A ∩ B b) A ∩ (A U B )’ = Ф

asambeis [7]

Answer:

a) From A ∩ A' = ∅, we have;

A ∩ (A' ∪ B) = A ∩ B

b) From A ∩ (A' ∩ B') = (A ∩ A') ∩ B' and A ∩ A' = ∅, we have;

A ∩ (A ∪ B)' = ∅

Step-by-step explanation:

a) By distributive law of sets, we have;

A ∩ (B ∪ C) = (A ∩ B) ∪ (A ∩ C)

From the complementary law of sets, we have;

A ∩ A' = ∅

Therefore, for A ∩ (A' ∪ B) = A ∩ B, we have

A ∩ (A' ∪ B) = (A ∩ A') ∪ (A ∩ B) (distributive law of sets)

A ∩ A' = ∅ (complementary law of sets)

Therefore;

(A ∩ A') ∪ (A ∩ B) = ∅ ∪ (A ∩ B) = (A ∩ B) (Addition to zero identity property)

∴ A ∩ (A' ∪ B) = A ∩ B

b) By De Morgan's law

(A ∪ B)' = A' ∩ B'

Therefore, A ∩ (A ∪ B)' = A ∩ (A' ∩ B')

By associative law of sets, we have;

A ∩ (A' ∩ B') = (A ∩ A') ∩ B'

A ∩ A' = ∅ (complementary law of sets)

Therefore, (A ∩ A') ∩ B' = ∅ ∩ B' = ∅

Which gives;

A ∩ (A ∪ B)' = ∅.

4 0

2 years ago