Question

As an aid to the establishment of personnel requirements, the director of a hospital wishes to estimate the mean number of people who are admitted to the emergency room during a 24 hour period. The director randomly selects 64 different 24-hour periods and determines the number of admissions for each. For this sample, he calculated a mean a 396 and a standard deviation of 100. The 95% confidence interval results in an interval of 396 +/- 24.9793. Identify the sampling error or margin of error.

Answer 1

Answer: 24.9793

Step-by-step explanation:

Given : The director randomly selects 64 different 24-hour periods and determines the number of admissions for each.

For this sample, he calculated a mean  $\overlien{x}=396$ and a standard deviation of 100.

The 95% confidence interval results in an interval of $396 \pm 24.9793$

We know that the confidence interval for population mean is given by :_

$\overlien{x}\pm E$, where E is the margin of error.

By comparing this to the given interval , we find that the margin of error = 24.9793