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Mamont248 [21]
3 years ago
11

Calculate the molarity of a solution prepared by dissolving 12.5 g of Na2CrO4 in enough water to produce a solution with a volum

e of 810. mL .
Chemistry
1 answer:
gregori [183]3 years ago
4 0

Answer:

0.0953M

Explanation:

First, let us calculate the number of mole present in 12.5g of Na2CrO4.

Molar Mass of Na2CrO4 = (23x2) + 52 +(16x4) = 46 + 52 +64 = 162g/mol

Mass of Na2CrO4 = 12.5g

Number of mole =?

Number of mole =Mass /Molar Mass

mole of Na2CrO4 = 12.5/162 = 0.0772mol

Now, we can calculate for the molarity as follows:

Mole = 0.0772mol

Volume = 810mL = 810/1000 = 0.81L

Molarity =?

Molarity = mole /Volume

Molarity = 0.0772mol/0.81L

Molarity = 0.0953M

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Choose the aqueous solution that has the highest boiling point. These are all solutions of nonvolatile solutes and you should as
FrozenT [24]

Answer:

0.100 M AlCl₃

Explanation:

The variation of boiling point by the addition of a nonvolatile solute is called ebullioscopy, and the temperature variation is calculated by:

ΔT = W.i

Where W = nsolute/msolvent, and i is the Van't Hoff factor. Because all the substances have the same molarity, n is equal for all of them.

i = final particles/initial particles

C₆H₁₂O₆ don't dissociate, so final particles = initial particles => i = 1;

AlCl₃ dissociates at Al⁺³ and 3Cl⁻, so has 4 final particles and 1 initial particle, i = 4/1 = 4;

NaCl dissociates at Na⁺ and Cl⁻ so has 2 final particles and 1 initial particle, i = 2/1 = 2;

MgCl₂ dissociates at Mg⁺² and 2Cl⁻, so has 3 final particles and 1 initial particle, i = 3/1 = 3.

So, the solution with AlCl₃ will have the highest ΔT, and because of that the highest boiling point.

8 0
4 years ago
7. What is the voltage when the resistance is 6 ohms and the current is 8 amps?
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Answer:

48 volts

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When do scientist rely on estimates
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Write the balanced equation and determine the information requested in each of the following.
Elena L [17]

Answer:

See explanation.

Explanation:

Hello!

In this case, we can proceed as follows:

1. Here, the undergoing chemical reaction is:

C_2H_2+\frac{5}{2} O_2\rightarrow 2CO_2+H_2O

Thus, the moles and mass of water turn out:

n_{H_2O}=20.0kgC_2H_2*\frac{1000gC_2H_2}{1kgC_2H_2} *\frac{1molC_2H_2}{26.04gC_2H_2} *\frac{1molH_2O}{1molC_2H_2}=768molH_2O\\\\m_{H_2O}=768molH_2O*\frac{18.02gH_2O}{1molH_2O}=13,840 gH_2O

2. Here, the undergoing chemical reaction is:

CaCO_3+2HCl\rightarrow CaCl_2+H_2O+CO_2

So the required moles of HCl and the yielded of water are:

n_{CaCO_3}=2.6molHCl*\frac{1molCaCO_3}{2molHCl}=1.3molCaCO_3\\\\ n_{H_2O}=2.6molHCl*\frac{1molH_2O}{2molHCl}=1.3molH_2O

3. Here, the undergoing chemical reaction is:

Al_2O_3+3H_2SO_4\rightarrow Al_2(SO_4)_3+3H_2O

Now, we apply each mole ratio obtain:

A.

n_{H_2SO_4}=2.6molAl_2O_3*\frac{3molH_2SO_4}{1molAl_2O_3} =7.8molH_2SO_4

B.

n_{Al_2(SO_4)_3}=2.6molAl_2O_3*\frac{1molAl_2(SO_4)_3}{1molAl_2O_3} =2.6molAl_2(SO_4)_3

Best regards!

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3 years ago
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