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Harrizon [31]
3 years ago
8

When do scientist rely on estimates

Chemistry
2 answers:
Brut [27]3 years ago
7 0
Scientist rely on their estimates when they cannot obtain on exact numbers 

Temka [501]3 years ago
4 0

Answer:

The correct answers will be- when the scientists do not not get the expected results in the form of the exact numbers.

Explanation:

Estimation is the process of approximation based on the uncertain or unexpected, unstable and incomplete data.

The process of estimation is sometimes followed by the scientists like when predicting the exact age of the Earth or the evolutionary facts of species which is impossible to predict and the data does not provide the exact numbers.

Thus, scientist relies on estimated when they do not get the expected results in the form of exact numbers.

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You have 4 moles of a gas in a 50 L container held at 2 atm pressure. Currently the temperature is 27 ºC. R = 0.0821 L*atm/(mol*
Mariulka [41]
The formula used for determining gas pressure, volume and temperature interaction would be PV=nRT. 

<span>• What is the temperature in Kelvins?
</span>You already right at this part. Kelvin temperature formula from celsius should be:
K= C+273.15= 
<span>K= 27 +273.15 = 300.15 
It is important to remember that the formula in this question is using Kelvin unit at temperature, not Celcius or Fahrenheit.
</span>
<span>• Assuming that everything else remains constant, what will happen to the pressure if the temperature decreases to -15 ºC?
</span>In this case, the temperature is decreased from 27C into -15C and you asked the change in the pressure.
Using PV=nRT formula, you can derive that the temperature will be directly related to pressure. If the temperature decreased, the pressure will be decreased too. 

<span> If you increase the number of moles to 6 moles, increase temperature to 400K and reduce the volume to 25 L, what will the new pressure be?
</span>PV=nRT
P= nRT/V
P= 6 moles* <span>0.0821 L*atm/(mol*K) * 400K/25L= 7.8816 atm</span>
3 0
3 years ago
Calculate the molarity of a solution that contains 3.11 mol of NaNO3 dissolved in 2.50 L. Enter your answer in the provided box.
rusak2 [61]

Answer:

Molarity of a solution that contains 3.11 mol of NaNO3 is 1,24 M

Explanation:

We understand molarity as the number of moles of solute that are contained in 1 L of solution, then if in a solution of 2.50 L we have 3.11 moles, it remains to calculate how many moles do we have in 1 liter.

2,50 L .......... 3,11 moles

1 L .................. x

X = ( 1 L x 3,11 moles) / 2,50 L = 1,24

8 0
3 years ago
(HELP FAST)Which of the following always changes when a substance undergoes a<br> chemical change?
Lera25 [3.4K]
I’m pretty sure it’s a
7 0
3 years ago
Read 2 more answers
4.5 moles of sodium sulfate contain how many atoms of sulfur
Hatshy [7]
Chemical Formula of Sodium Sulfate is Na₂SO₄.

As we know, 1 mole of any substance contains 6.022 × 10²³ particles. So, 1 mole of Na₂SO₄ also contains 6.022 × 10²³ formula units of Na₂SO₄.
Also,
                     1 mole of Na₂SO₄ contains  =  6.022 × 10²³ Atoms of S
So,
            4.5 moles of Na₂SO₄ will contain  =  X atoms of S

Solving for X,
                                X  =  (4.5 moles × 6.022 × 10²³ Atoms) ÷ 1 mole

                                X  =  2.70 × 10²⁴ Atoms of S
Result:
            4.5 Moles 
of Na₂SO₄ contains 2.70 × 10²⁴ Atoms of Sulfur.
3 0
3 years ago
A 32 g sample of LiCl is dissolved in water to for 655 mL of solution. What is the molarity of the solution?
emmainna [20.7K]

Answer : The molarity of the solution is, 1.1 M LiCl

Explanation : Given,

Mass of LiCl = 32 g

Volume of solution = 655 mL

Molar mass of LiCl = 42.4 g/mole

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

\text{Molarity}=\frac{\text{Mass of }LiCl\times 1000}{\text{Molar mass of }LiCl\times \text{Volume of solution (in mL)}}

Now put all the given values in this formula, we get:

\text{Molarity}=\frac{32g\times 1000}{42.4g/mole\times 655mL}=1.1mole/L=1.1M

Therefore, the molarity of the solution is, 1.1 M LiCl

3 0
3 years ago
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