Answer:
Carbon is released back into the atmosphere when organisms die, volcanoes erupt, fires blaze, fossil fuels are burned, and through a variety of other mechanisms.Humans play a major role in the carbon cycle through activities such as the burning of fossil fuels or land development.
Answer:

Explanation:
Molarity is a measure of concentration in moles per liter.

The molarity of the solution is 1.2 M NaNO₃ or 1.2 moles NaNO₃ per liter. There are 0.25 liters of the solution. The moles of solute are unknown, so we can use x.
- molarity= 1.2 mol NaNO₃/L
- liters of solution=0.25 L
- moles of solute =x

We are solving for x, so we must isolate the variable, x. It is being divided by 0.25 liters. The inverse of division is multiplication, so we multiply both sides by 0.25 L.


The units of liters cancel, so we are left with the units moles of sodium nitrate.


There are 0.3 moles of sodium nitrate.
Answer:
Gravitational force is directly promotional to the mass
of both interacting objects.
Explanation:
More massive objects will attract each other with
a greater gravitional force. So as the mass of the
either objects increases the force of gravitational
attraction between them also increases.
Answer: option B. - A, B, D, E, C, H, F, G is correct using the principle of cross-cutting relationships.
The principle of cross-cutting relationships states that a fault or intrusion is younger than the rocks that it cuts through.
Explanation:
The full sequence of events is:
1. Layer A formed.
2. Layer B formed
3. Layer D formed.
4. Layer E formed
5. After layers A-B-D-E were present, intrusion C cut across all three.
6. Fault H formed, shifting rocks E through A and intrusion C.
7. Weathering and erosion created a layer of soil on top of layer F then G.
The reason for adding a limited amount and then an excess amount is that initially a metal hydroxide may form which becomes soluble when more base is added and the metal complex forms.
In qualitative analysis is a common to add the base in drops and then in excess. When added in drops, the metal hydroxide is formed. This metal hydroxide is often insoluble.
After this metal hydroxide is formed, the base could be added in excess such that the metal hydroxide dissolves in the excess base by forming a complex.
For instance;
CuCl2(aq) + 2NaOH(aq) -------> Cu(OH)2(s) + 2NaCl(aq)
Cu(OH)2(s) + 2OH^-(aq) -------> [Cu(OH)4]^2+(aq)
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