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dybincka [34]
4 years ago
8

A chemical reaction gives off 1,500 kj of heat energy. about how many calories is this? (1 calorie = 4.18 joules)

Chemistry
2 answers:
Greeley [361]4 years ago
6 0
1500kj = 15x 10^5 j
1 calorie = 4.18 j
(15 x 10^5)/4.18= 3.58 x 10^5

Answer is a
Zanzabum4 years ago
3 0

Answer is: a. 3.6 x 10^5 calories.  

E = 1500 kJ; heat energy.

E = 1500 kJ · 1000 J/kJ.

E = 1500000 J = 1.5·10⁶ J.

E = 1.5·10⁶ J ÷ 4.18 J/cal.

E = 3.6·10⁵ cal.

Calorie (cal), or small calorie, is the amount of energy needed to heat one gram of water by one degree Celsius.

One small calorie is approximately 4.18 joules.

A calorie is a unit of energy.


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Which place on earth would be likely to have the most humidity due to water vapor in the atmosphere? Moscow, Russia Toronto, Can
mel-nik [20]

Answer:

Nassau, Bahamas

Explanation: The Bahamas are close to the equator so it has more heat which means higher water evaporation which leads to a higher humidity than the other places.

6 0
3 years ago
The reaction for photosynthesis producing glucose sugar and oxygen gas is:
Anvisha [2.4K]

<u><em>1.5 grams of glucose is produced from 2.20 g of CO₂.</em></u>

To find the mass of glucose produced, first you must know the balanced reaction. For this, the Law of Conservation of Matter is followed.

The law of conservation of matter states that since no atom can be created or destroyed in a chemical reaction, the number of atoms that are present in the reagents has to be equal to the number of atoms present in the products.

So, in this case, the balanced reaction is:

6 CO₂ + 6 H₂O → C₆H₁₂O₆ + 6 O₂

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the amounts of moles of each reactant and product participate in the reaction:

  • CO₂: 6 moles
  • H₂O: 6 moles
  • C₆H₁₂O₆: 1 mole
  • O₂: 6 moles

So, you know that 2.20 g of CO₂ react, whose molar weight is 44.01 g/mole. By definition of molar mass, 1 mole of CO₂ has 44.01 g. So, the number of moles that 2.20 grams of the compound represent is calculated as:

moles of CO_{2} =2.20 grams*\frac{1 mole}{44.01 grams}

moles of CO₂= 0.05 moles

Now you must follow the following rule of three: if by stoichiometry of the reaction 6 moles of CO₂ produce 1 mole of C₆H₁₂O₆, 0.05 moles of CO₂ produce how many moles of C₆H₁₂O₆?

moles of C_{6} H_{12} O_{6} =\frac{0.05moles of CO_{2} *1 mole of C_{6} H_{12} O_{6}}{6moles of CO_{2}}

moles of C₆H₁₂O₆= 8.33*10⁻³

Being the molar mass of glucose 180.18 g/mole, the mass that 8.33*10⁻³ moles of the compound represent is calculated as:

mass of glucose =8.33*10^{-3} moles*\frac{180.18 grams}{1 mole}

<em>mass of glucose= 1.5 grams</em>

Then, <u><em>1.5 grams of glucose is produced from 2.20 g of CO₂.</em></u>

5 0
3 years ago
Identify the base-conjugate acid pair in this balanced equation:
Elan Coil [88]
<h3><u>Answer;</u></h3>

NH3/NH4+

<h3><u>Explanation;</u></h3>

From the equation;

NH3(aq)+HNO3(aq)→NH4+(aq)+NO3−(aq)  

NH3 is the base; while NH4+ is the conjugate acid  

HNO3 is the acid; while NO3- is the conjugate base  

  • The conjugate base of a Brønsted-Lowry acid is species that is formed after an acid donates a proton while the conjugate acid of a Brønsted-Lowry base is the species formed after a base accepts a proton.
3 0
3 years ago
Read 2 more answers
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Ivahew [28]
<h3>Answer:</h3>

Group 5A

<h3>Explanation:</h3>
  • Elements in the periodic table are arranged into columns known as groups and rows known as periods.
  • Elements in the same group share similar chemical properties.
  • For example, elements in group 5A have five valence electrons with the most high energy level with a configuration of s²p³.
  • Elements in group 5A include nitrogen and phosphorus among others.
5 0
4 years ago
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Natali5045456 [20]

(a) We know that work is the product of Force and Distance so: (in this case Distance is negative since going down so –d)

work = force * distance

work = M * (g - g/4) * -d

work = -3Mgd/4 <span>

(b) The work by the weight of the block is simply:</span>

work = Mgd <span>

(c) The kinetic energy is simply equivalent to the net work, therefore:</span>

KE = net work

KE = Mgd/4 <span>

(d) The velocity is:</span>

v = √(2*KE/M)

Plugging in the value of KE from c:

v = √(2*Mgd / 4M)

<span>v = √(gd / 2) </span>

5 0
3 years ago
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