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BARSIC [14]
3 years ago
12

Wilbur Wright was born in 1867. His brother Orville was born in 1871. How old was each brother in 1903?

Mathematics
1 answer:
miss Akunina [59]3 years ago
6 0
36 and 32, respectively.
I am the primary school student.
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A coffee packaging plant claims that the mean weight of coffee in its containers is at least 32 ounces. A random sample of 15 co
Luda [366]

Answer:

We conclude that the mean weight of coffee in its containers is at least 32 ounces which means that the data support the claim.

Step-by-step explanation:

We are given that a coffee packaging plant claims that the mean weight of coffee in its containers is at least 32 ounces.

A random sample of 15 containers were weighed and the mean weight was 31.8 ounces with a sample standard deviation of 0.48 ounces.

Let \mu = <u><em>mean weight of coffee in its containers.</em></u>

SO, Null Hypothesis, H_0 : \mu \geq 32 ounces     {means that the mean weight of coffee in its containers is at least 32 ounces}

Alternate Hypothesis, H_A : \mu < 32 ounces      {means that the mean weight of coffee in its containers is less than 32 ounces}

The test statistics that would be used here <u>One-sample t-test statistics</u> as we don't know about population standard deviation;

                             T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean weight = 31.8 ounces

             s = sample standard deviation = 0.48 ounces

             n = sample of containers = 15

So, <u><em>the test statistics</em></u>  =  \frac{31.8 -32}{\frac{0.48}{\sqrt{15} } }  ~ t_1_4  

                                      =  -1.614

The value of t test statistics is -1.614.

<u>Now, at 0.01 significance level the t table gives critical value of -2.624 at 14 degree of freedom for left-tailed test.</u>

Since our test statistic is more than the critical value of t as -1.614 > -2.624, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u><em>we fail to reject our null hypothesis</em></u>.

Therefore, we conclude that the mean weight of coffee in its containers is at least 32 ounces which means that the data support the claim.

8 0
3 years ago
If the federal reserve sells 70,000 in treasury bonds to a bank at 9%
Anton [14]

Answer:

it is decreased by $70,000

Step-by-step explanation:

Federal reserve sells $70,000 in treasury bonds to a bank at 9%

6 0
3 years ago
In 2007 the population of the town of Cartersville was 24,455. The population growth can be represented by the formula P = 24,45
Triss [41]
P = 24455 (1.03)x
30,000/24455 (1.03) < x
The year must be > 1.19 + 2007, or 2008.19, which means in 2009, or in 2008 + 3 months
3 0
2 years ago
A and B working together can do a work in 6 days. If A takes 5 days less than B to finish the work, in how many days B alone can
svetlana [45]

Answer:

15 days

Step-by-step explanation:

Let x be the number of days needed for B to complete the job. Then x-5 is the number of days needed for A to complete the job.

In 1 day,

  • A completes \dfrac{1}{x-5} of all work;
  • B completes \dfrac{1}{x} of all work.

Hence, in 1 day both A and B complete \dfrac{1}{x-5}+\dfrac{1}{x} of all work. A and B working together can do a work in 6 days. Then

6\cdot \left(\dfrac{1}{x-5}+\dfrac{1}{x}\right)=1.

Solve this equation:

\dfrac{6x+6x-30}{x(x-5)}=1,\\ \\12x-30=x^2-5x,\\ \\x^2-17x+30=0,\\ \\D=(-17)^2-4\cdot 30=289-120=169=13^2,\\ \\x_{1,2}=\dfrac{17\pm 13}{2}=2,\ 15.

If x=2, then x-5=-3 that is impossible. So, B needs 15 days to complete the work alone.

6 0
2 years ago
Find the cost per visit to the nearest cent body fit $238 per year 95
AfilCa [17]
The answer of this question is $2.51
4 0
2 years ago
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