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2 years ago

What do I plug into a calculator to find the value of 777 after a 7% increase?

Mathematics

2 answers:

GuDViN [60]2 years ago

8 0

Answer:

Step-by-step explanation:

you do a because there is a 7% increase (times 0.07) and add 1 because the original value dosnt leave

melamori03 [73]2 years ago

5 0

A because 777x1.00 would be 777. The .07 percent is the 7 percent increase

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Multiply (x + 2y)(x2 − xy + 3y).

erma4kov [3.2K]

Answer:

${x}^{3} + {x}^{2} y + 3xy - 2x {y}^{2} + 6 {y}^{2}$

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2 years ago

A person gets on and off a bathroom scale four times. The four readings (in pounds) are 148, 151, 150, and 152. Each time after

Ganezh [65]

Answer:

See explanation below

Step-by-step explanation:

Since each time after the person gets off the scale, the reading is 2 lb the person's weight must be near the mean of

148-2, 151-2, 150-2, 152-2; that is to say, near the mean of 146, 149, 148, 150 = (146+149+148+150)/4 = 148.25

We could estimate the uncertainty as the standard error SE

$\bf SE=\frac{s}{\sqrt{n}}$

where

s = standard deviation of the sample

n = 4 sample size.

Computing s:

$\bf s=\sqrt{\frac{(146-148.25)^2+(149-148.25)^2+(148-148.25)^2+(150-148.25)^2}{4}}=1.479$

So, the uncertainty is 1.479/2 = 0.736

It is not possible to estimate the bias, since it is the difference between the true weight and the mean, but we do not know the true weight.

5 0

3 years ago

A survey of 85 families showed that 36 owned at least one DVD player. Find the 99% confidence interval estimate of the true prop

attashe74 [19]

Answer:

$0.424 - 2.58\sqrt{\frac{0.424(1-0.424)}{85}}=0.286$

$0.424 + 2.58\sqrt{\frac{0.424(1-0.424)}{85}}=0.562$

The 99% confidence interval would be given by (0.286;0.562)

Step-by-step explanation:

Information given:

$X= 36$ represent the families owned at least one DVD player

$n= 85$ represent the total number of families

$\hat p=\frac{36}{85}= 0.424$ represent the estimated proportion of families owned at least one DVD player

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by $\alpha=1-0.99=0.01$ and $\alpha/2 =0.05$ . And the critical value would be given by: