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sergejj [24]
3 years ago
5

Answers of science book​

Engineering
1 answer:
vitfil [10]3 years ago
6 0

Answer:  answers of science book  is to help you

Explanation: if there are answer in a science book use them there for a reason

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What's the difference between accuracy and percision in measuring and gaging?
lidiya [134]

Answer:

The term Accuracy means that how close our result to the original result.

Suppose we do any experiment in laboratory and we calculate mass = 7 kg but answer is mass = 15 kg then our answer is not accurate.

And the term Precision means how likely we get result like this.

Suppose we do any experiment in laboratory and we calculate mass five times and each time we get mass = 7 kg then our answer is precised but not accurate.

4 0
3 years ago
Free random points because im bored
tamaranim1 [39]

Answer:

thx for points B)

Explanation:

8 0
3 years ago
Read 2 more answers
Write the Different types of Trainings and explain Anyone in short​
Eddi Din [679]

Answer:

Coaching or mentoring

Coaching or mentoring can share similar qualities to hands-on training, but in this type of employee training, the focus is on the relationship between an employee and a more experienced professional, such as their supervisor, a coach, or a veteran employee.

The one-on-one mentoring style creates a relationship between employees that carries far beyond training. Lecture-style training

Important for getting big chunks of information to a large employee population, lecture-style training can be an invaluable resource for communicating required information quickly.

However, use this type of employee training sparingly.

3 0
2 years ago
You will write a program estimate that uses a training data set to learn weights for a set of house attributes, and then applies
gizmo_the_mogwai [7]

Answer:

I can share a link to answer since the code is to long to be contained here. the code is on github

https://github.com/arafatm/edu_coursera_machine_learning_1_foundations/blob/master/code/02.01.predicting.house.prices.ipynb

5 0
3 years ago
An adiabatic gas turbine expands air at 1300 kPa and 500◦C to 100 kPa and 127◦C. Air enters the turbine through a 0.2-m2 opening
Viktor [21]

Given:

Pressure, P_{1} = 1300 kPa

Temperature,  T_{1} = 500^{\circ}

P_{2} = 100 kPa

T_{2} = 127^{\circ}  

velocity, v = 40 m/s

A = 1m^{2}

Solution:

For air propertiess at

P_{1} = 1300 kPa

T_{1} = 500^{\circ}

h_{1} = 793kJ/K

v_{1} = 0.172\frac{m^{3}}{kg}

and also at

P_{2} = 100 kPa

T_{2} = 127^{\circ}  

h_{2} = 401 KJ/K

v_{2} =  1.15\frac{m^{3}}{kg}

a) Mass flow rate is given by:

m' = \frac{Av}{v_{1}}

Now,

m = \frac{0.2\times 40}{0.172} = 46.51 kg/s

b) for the power produced by turbine, P = m'(h_{1} - h_{2})

P = 46.51\times(793 - 401) = 18.231 MW

5 0
3 years ago
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