Answer:
Explanation:
Hello,
In this case, for the inlet stream, from the steam table, the specific enthalpy and entropy are:
Next, for the liquid-vapor mixture at the outlet stream we need to compute its quality by taking into account that since the turbine is adiabatic, the entropy remains the same:
Thus, the liquid and liquid-vapor entropies are included to compute the quality:
Next, we compute the outlet enthalpy by considering the liquid and liquid-vapor enthalpies:
Then, by using the first law of thermodynamics, the maximum specific work is computed via:
Best regards.
Answer:
Therefore, the horizontal displacement of end F of rod EF is 0.4797 mm
Explanation:
solution is mentioned in steps.
Answer:
common fate
Explanation:
The gestalt effect may be defined as the ability of our brain to generate the whole forms from the groupings of lines, points, curves and shapes. Gestalt theory lays emphasis on the fact that whole of anything is much greater than the parts.
Some of the principles of Gestalt theory are proximity, similarity, closure, symmetry & order, figure or ground and common fate.
Common fate : According to this principle, people will tend to group things together which are pointed towards or moving in a same direction. It is the perception of the people that objects moving together belongs together.
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Answer:
10.203 Volts
Explanation:
For this problem, we need to understand that a series resistive circuit is simply a circuit with some type of voltage source and some resistors, in this case, R1 and R2.
First, we need to find the voltage in the circuit. To do this, we need to find the total resistance of the circuit. When two resistors are in series, you sum the resistance. So we can say the following:
R_Total = R1 + R2
R_Total = 570 Ω + 560 Ω
R_Total = 1130 Ω
Now that we have R_Total for the circuit, we can find the voltage of the circuit by using Ohm's law, V = IR.
V_Total = I_Total * R_Total
V_Total = 17.9 mA * 1130 Ω
V_Total = 20.227 V
Now that we have V_Total, we can find the voltage drop across each resistor by using Ohm's law once more. Note, that since our circuit is series, both resistors will have the same current (I.e., I_Total = I_1 = I_2).
V_Total = V_1 + V_2
V_Total = V_1 + I_2*R2
V_Total - I_2*R2 = V_1
20.227 V - (17.9 mA * 560 Ω) = V_1
20.227 V - (10.024 V) = V_1
10.203 V = V_1
Hence, the voltage drop across R1 is 10.203 Volts.
Cheers.
