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2 years ago

The team needs to choose a primary view for the part drawing. Three team members make suggestions:

Engineering

1 answer:

dexar [7]2 years ago

6 0

Answer:

<u>Option 1</u>

Explanation:

As the team has already submitted the plans for the part drawing, the best way to proceed would be how it was given in the plans. Hence, the option to be selected :

<u>Team member 1 suggests an orthographic top view because that is how the plans for the part were submitted.</u>

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“We have to redo the deck we built last week,” Bennett tells his coworkers. “I just tested it, and it doesn’t hold the minimum w

PIT_PIT [208]

Answer:

Consumer-driven

Explanation:

Bcz he told the cost of money

5 0

2 years ago

9 b. A sign (including the post and base) weighs 40 pounds and is

tigry1 [53]

Answer:

The weight should be added to the base of the sign to keep it from tipping is 65.6 lb

Explanation:

Given data:

A sigh weighs 40 pounds

Suported by an 18 in x 18 in square

Force of the wind 13.2 lb

Questions: Will the sign tip over, if yes, how much evelnly distributed weight should be added to the base of the sign to keep it from tipping, W = ?

The sign and the post have a length of 6 ft. You need to calculate the distance from the edge to the middle point:

18/2 = 9 in = 0.75 ft

Force acting in the base (40 lb):

$F=\frac{40*0.75}{6} =5lb$

The weight should be added to the base:

$(40+W)*\frac{0.75}{6} =13.2\\W=65.6lb$

8 0

4 years ago

The Prince Company, Inc has 100 employees. In 2009, the employees worked a total of 350,000 hours annual and reported 145 injuri

Helga [31]

Answer:

For 145 injuries, IR=82.86 // For 79 injuries, IR=45.14

Explanation:

As stablished by OSHA, incident rate (IR) is used as a measurement to compare a company's safety against the national average. It is calculated by multiplying the number of recordable cases by 200.000 and then dividing the result by the number of total labor hours of the company.

For 145 injuries:

IR= (145*200.000)/350.000 = 82.86

For 79 injuries:

IR= (79*200.000)/350.000 = 45.14

3 0

3 years ago

Determine the COP of a refrigerator that removes heat from the food compartment at a rate of 5160 kJ/h for each kW of power it c

Mars2501 [29]

Answer:

$COP_R=1.433\\Q_H=2.433kW$

Explanation:

Hello,

In this case, the coefficient of performance of this refrigerator is defined in terms of the removed heat and the work input as:

$COP_R=\frac{Q_{L}}{W_{in}} =\frac{5160\frac{kJ}{h}*\frac{1h}{3600s} }{1kJ/s} =1.433$

Moreover, the rate of heat rejection to the outside air tuns out:

$W_{in}=Q_H-Q_L\\Q_H=W_{in}+Q_L=1kW+5160\frac{kJ}{h}*\frac{1h}{3600s} =2.433kW$

Best regards.

3 0

3 years ago

Read 2 more answers

Evaluate to three significant figures and using appropriate prefix: (354 mg)(45 km)/(0.0356 kN)

frutty [35]

Answer:

0.447 s²

Explanation:

First, convert to SI units.

(354 mg) (45 km) / (0.0356 kN)

(0.354 g) (45000 m) / (35.6 N)

One Newton is kg m/s²:

(0.354 g) (45000 m) / (35.6 kg m/s²)

(0.000354 kg) (45000 m) / (35.6 kg m/s²)

Simplify:

0.447 s²

5 0

3 years ago