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2 years ago

The team needs to choose a primary view for the part drawing. Three team members make suggestions:

Engineering

1 answer:

dexar [7]2 years ago

6 0

Answer:

Option 1

Explanation:

As the team has already submitted the plans for the part drawing, the best way to proceed would be how it was given in the plans. Hence, the option to be selected :

Team member 1 suggests an orthographic top view because that is how the plans for the part were submitted.

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A blown fuse or tripped circuit breaker shows

aleksklad [387]

Answer:

Your house is in need of a service upgrade, or it may indicate that your house has too few circuits.

Explanation:

It's a sign that you are making excessive demands on the circuit and need to move some appliances and devices to other circuits.

6 0

3 years ago

You were recently hired by the Andrews CEO as a consultant to evaluate the performance of the Chief Financial Officer (CFO). As

goldfiish [28.3K]

Answer: Collect more information about the extent to which this reported behavior is impacting others

Explanation:

The options are:

a. Collect more information about the extent to which this reported behavior is impacting others.

b. Tell the CEO about what you have uncovered and ask for her permission to speak about it with the CFO.

c. Focus on the CFO’s work performance since his personal behavior is inappropriate in the workplace.

d. Inform the human resources department that there is a potential problem.

Given the information provided in the question, the most effective next step in the process will be to collect more information about the extent to which this reported behavior is impacting others. This will be vital in determining whether what is being said about the Chief Financial Officer is true or not and also to know if true, whether it has an affect on the performance of affected employees in the organization.

Option B is wrong as telling the CEO right away isn't the next step as adequate information must be gathered first.

Option C is also wrong as the focus shouldn't be on his work in the organization alone. His personal behavior should be addressed as well if he's wrong. A great organization is made up of great individuals with good behaviors.

Option D is also wrong as the next step should not be to inform the human resource.

Therefore, the correct option is A.

5 0

3 years ago

If an object is near the surface of the earth the variation of its weight with distance from the center of the earth can ofteb b

zalisa [80]

Answer:

h=32.1 km

Explanation:

solution:

using newton law of gravitational attraction and newton second law:

$W=\frac{Gmm_{E} }{r^{2} } \\a=\frac{Gm_{E}}{r^{2}} \\W=ma\\$

$m_{E}= mass of earth$

r= distance between two masses

at sea level

a=g

$r=R_{E}$

$a=\frac{Gm_{E}}{r^{2}}$ .............................(1)

$Gm_{E} =gR_{E}^2$ .........................(2)

by substituting (2) and (1) $a=g\frac{R_{E}^2 }{r^{2} }$ acceleration due to gravity at a distance r from the centre of the earth in terms of g (sea level)

so the weight of the object at a distance r from the centre of the earth (W=ma)

W=mg(Re^2/r^2)..........(3)

h the height above the surface of the earth: r=Re+h

putting the value of r in eq (3)

W=mg(Re/Re+h)^2

W=0.99 mg

solving for height h:

h=Re(1/√0.99)-(1))

h=32.1 km

4 0

3 years ago

Oil with a kinematic viscosity of 4 10 6 m2 /s fl ows through a smooth pipe 12 cm in diameter at 2.3 m/s. What velocity should w

Setler79 [48]

Answer:

Velocity of 5 cm diameter pipe is 1.38 m/s

Explanation:

Use following equation of Relation between the Reynolds numbers of both pipes

$Re_{5}$ = $Re_{12}$

$\sqrt{\frac{V_{5}XD_{5} }{v_{5}}}$ = $\sqrt{\frac{V_{12}XD_{12} }{v_{12}}}$

$Re_{5}$ = Reynold number of water pipe

$Re_{12}$ = Reynold number of oil pipe

$V_{5}$ = Velocity of water 5 diameter pipe = ?

$V_{12}$ = Velocity of oil 12 diameter pipe = 2.30

$v_{5}$ = Kinetic Viscosity of water = 1 x $10^{-6}$ $m^{2}$ /s

$v_{12}$ = Kinetic Viscosity of oil = 4 x $10^{-6}$ $m^{2}$ /s

$D_{5}$ = Diameter of pipe used for water = 0.05 m

$D_{12}$ = Diameter of pipe used for oil = 0.12 m

Use the formula

$\sqrt{\frac{V_{5}XD_{5} }{v_{5}}}$ = $\sqrt{\frac{V_{12}XD_{12} }{v_{12}}}$

By Removing square rots on both sides

${\frac{V_{5}XD_{5} }{v_{5}}}$ = ${\frac{V_{12}XD_{12} }{v_{12}}}$

${V_{5}$ = ${\frac{V_{12}XD_{12} }{v_{12}XD_{5}\\}}$ x $v_{5}$

${V_{5}$ = [ (0.23 x 0.12m ) / (4 x $10^{-6}$ $m^{2}$ /s) x 0.05 ] 1 x $10^{-6}$ $m^{2}$ /s

${V_{5}$ = 1.38 m/s

4 0

4 years ago

What is the normal balance side of an asset?

Mademuasel [1]

The normal balance for asset and expense accounts is the debit side, while for income, equity, and liability accounts it is the credit side. An account's assigned normal balance is on the side where increases go because the increases in any account are usually greater than the decreases

8 0

3 years ago