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ANEK [815]
3 years ago
9

Find a real number c such that x^(2)+12x+c is a perfect square trinomial.

Mathematics
1 answer:
balu736 [363]3 years ago
8 0

Answer:

The value of c is 36

Step-by-step explanation:

Now, we fine the perfect square polynomial, we need to have the expression of the form:

a^2+b^2+2ab

so this can be written as a perfect square as: a^2+b^2+2ab= (a+b)^2

Now the expression given to us is:

x^{2}+12x+c

so when c is 36, we will get:

x^{2}+12x+c= x^(2)+12x+36

Now, this can be re-written as:

x^{2}+2*6*x+6^2

so here we can see that it is of the form:

a^2+b^2+2ab

so the perfect square is:

x^(2)+2*6*x+6^2= (x+6)^2

Hence, when c = 36 we get a perfect square.

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Enter an algebraic expression to model the given context. Give your answer in simplest form. The original price p of an item les
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Step-by-step explanation:

Let

Original price = p

Less Discount = 20%

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2 years ago
Solve ln 2 + ln x = 5. Round to the nearest thousandth, if possible.
azamat

Answer:

The  value of x nearest to thousandths is, 74.207

Step-by-step explanation:

Solve :  \ln 2 + \ln x = 5

\ln represents the logarithmic function with base e.

Using logarithmic properties:

  • \ln (mn) = \ln m + \ln n
  • \ln x = a , then x = e^a

\ln 2 + \ln x = 5

Apply the logarithmic properties; we have

\ln 2x = 5

then;

2x = e^5

or

2x=148.41315910258

Divide both sides by 2 we get;

x = 74.2065796

Therefore, the value of x nearest to thousandths is, 74.207

3 0
3 years ago
How would i solve this
Ivahew [28]

#1

\\ \sf\longmapsto f(-3)

\\ \sf\longmapsto -(-3)^2=-9

#2

\\ \sf\longmapsto f(-5)

\\ \sf\longmapsto 5(-5)-2=-25-2=-27

#3

\\ \sf\longmapsto f(-6)=5(-6)-2=-30-2=-32

7 0
2 years ago
Read 2 more answers
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