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1 answer:
5. y = -3 x - 8
6. y = - 1/2 x + 1
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Let sister be s. Matthew, M
Matthew is 7years older than twice the age of his sister
M = 7 + 2s
13 = 7 + 2s. 7 crosses the equality to other side and becomes -7
13 - 7 = 2s
6 = 2s Divide both sides by 2
6/2 = 2s/2
3 = s
Sister is 3 years old.
Your equation should be
y=2.2x
ANSWER

EXPLANATION
We want to simplify

The fractions have the same denominator so we write one denominator and add the numerators to obtain,

Regroup in the denominator to get,

This simplifies to;
i have to poop hhhhhjhhjhjhjhjhjhjhh
Answer:
<h3>Question 1</h3>
- sec²θ + cosec²θ =
- 1/cos²θ + 1/sin²θ =
- (sin²θ + cos²θ)/(sin²θcos²θ) =
- 1 / (sin²θcos²θ) =
- [(sin²θ + cos²θ)/sinθcosθ]² =
- (sinθ/cosθ + cosθ/sinθ)² =
- (tanθ + cotθ)²
<h3>Question 2</h3>
- (1 - tan²θ) / (1 + tan²θ) =
- (1 - sin²θ/cos²θ) / (1 + sin²θ/cos²θ) =
- (cos²θ - sin²θ) / (cos²θ + sin²θ) =
- (cosθ + sinθ)(cosθ - sinθ) / 1 =
- (cosθ + sinθ)(cosθ - sinθ)
<h3>Question 3</h3>
- sinθ/ (1 - cotθ) + cosθ / (1 - tanθ) =
- sinθ / (1 - cosθ/sinθ) + cosθ / (1 - sinθ/cosθ) =
- sinθ/ [(sinθ - cosθ) / sinθ] + cosθ / [(cosθ - sinθ)/cosθ] =
- sin²θ/ (sinθ - cosθ) + cos²θ/(cosθ - sinθ) =
- sin²θ/ (sinθ - cosθ) - cos²θ/(sinθ - cosθ) =
- (sin²θ - cos²θ) / (sinθ - cosθ) =
- (sinθ + cosθ)(sinθ - cosθ) / (sinθ - cosθ) =
- sinθ + cosθ