If <em>a</em> is the first term of an AP with common difference -2, then the first several terms are
<em>a</em>, <em>a</em> - 2, <em>a</em> - 4, <em>a</em> - 6, <em>a</em> - 8, …
with <em>n</em>-th term <em>a</em> - 2 (<em>n</em> - 1).
The sum of the first <em>n</em> terms is equal to the sum of the first 3<em>n</em> terms :

We have

so that in the previous equation, the sums reduce to

Solve for <em>a</em> :

Now if <em>a</em> = 27, we have
27 = 4<em>n</em> - 1
28 = 4<em>n</em>
<em>n</em> = 7
as required.
Answer:
C
Step-by-step explanation:
y+14=5
-14 -14
y=-9
Hope it helps :)
You divide 146 from 24 and get 6 with a few extra students, so you add another bus for those students, meaning 7 buses are needed total.
Answer:
2
Step-by-step explanation:
2
Answer:
I believe your answer would be C. square root of 67
Step-by-step explanation:
If 8 is the square root of 64 and the missing number is just over 8, square root of 72 would be too much and A. and D. would be too little. I do deeply apologize if this is incorrect.