What is the x-intercept of the line containing the point (-6,10) and (12,-2)?
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Answer:
Step-by-step explanation:
y=-3x+13
y = mx + b, where m is the slope and b is the y-intercept.
A line parallel to this line will have the same slope, -3. We can start by writing:
y = -3x + b
No matter what is chosen for the value of b, this line will be parallel. We do want the line to go through point (6,10), however. The way that can be done is to find a value of b that would shift the line to go through (6,10).
Find b by entering the point (6,10) into the equation, and then solve for b:
y = -3x + b
10 = -3(6) + b
10 = -18 + b
b = 28
The line becomes y = 3x + 28
See the attachment.
