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vazorg [7]
3 years ago
8

What is -0.8a-8=0.2a ?

Mathematics
1 answer:
nikklg [1K]3 years ago
8 0
I hope this helps you

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(04.01)The Baldwin family walked 4/5 of a mile in 4/9 of an hour. What is their unit rate in miles per hour?
sertanlavr [38]
Hello!

Since we know how much they walked in 4/9 of an hour, we will divide 4/5 by 4/9 to get 4/9 to one.

\frac{4}{5}÷\frac{4}{9}=\frac{36}{20} =  \frac{9}{5}

They went 1 4/5 mph or 1.8 mph.

I hope this helps!
7 0
3 years ago
Read 2 more answers
Select the correct answer from each drop-down menu.
Aleksandr [31]

Answer:

b

Step-by-step explanation:

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3 years ago
a recipe for making 4 cups of soup requires 3 cups of water at this rate how many cups of water are required to make 24 cups of
Tema [17]

Answer:

18

Step-by-step explanation:

4 divided by 24 is 6

6x3=18

8 0
3 years ago
A guitar string has a number of frequencies at which it will naturally vibrate when it is plucked. These natural frequencies are
AlladinOne [14]

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Step-by-step explanation:

4 0
2 years ago
The square root of a negative number, such as StartRoot negative 144 EndRoot, is undefined. Explain why the square root of –x, S
monitta

Part A

The reason why the (√(-x)) is not necessarily undefined, is because x is a placeholder, such that x can take on a negative value for which  (-x) is a positive number, therefore, √(-x) = √(+ve number) is a defined real number.

Part B

The domain is x ≤ 0

The range is f(x) ≥ 0

<h3>What is Real Number?</h3>

A real number is a value of a continuous quantity that can represent a distance along a line.

Here, The given and required information:

Given that √(-144) = Undefined, why is √(-x) not necessarily undefined

The given function, f(x) = √(-x)

Part A

The square root of a real number with a negative value is an imaginary number

The square root of a real number with a positive value or zero, is a real number

√(144) = ±12

A variable, x, is an input value of a function that is a quantity place holder in the function which is a function argument

The given function is f(x) = √(-x)

Where;

x = An argument of the function

When x ≤ 0, such that x is a negative real number or zero, we have;

x = R⁻ or 0

Therefore;

-x= -R⁻ or 0 = R⁺ or 0

-x = R⁺

From which we get;

f(-x)= √(-x) = √(R⁺) = Defined

f(-x) = √(R⁺) ≥ 0 The range of the function is f(x) ≥ 0

An example, when x = -16, we have;

-x = -(-16) = 16

√(-x) √(16) = 4 (Defined)

Part B;

Thee domain where the function is defined is where x = -R⁻,  x ≤ 0

The output of the function f(x) is defined which is the range = f(x) ≥ 0

Thus, the reason why the √(-x) is not  necessarily undefined, is because the value of x can represent a negative real number or zero.

Learn more about real numbers here;

brainly.com/question/17201233

#SPJ1

6 0
1 year ago
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