Answer:
Explanation:
There would be allaround 30 on the side.
Answer:
They use principles of light to scan document
Magnetic scanning
Explanation:
Complete Question:
Determine the number of cache sets (S), tag bits (t), set index bits (s), and block offset bits (b) for a 4096-byte cache using 32-bit memory addresses, 8-byte cache blocks and a 8-way associative design. The cache has :
Cache size = 1024 bytes, sets t = 26.8, tag bits, s = 3.2, set index bit =2
Answer:
Check below for explanations
Explanation:
Cache size = 4096 bytes = 2¹² bytes
Memory address bit = 32
Block size = 8 bytes = 2³ bytes
Cache line = (cache size)/(Block size)
Cache line =
Cache line = 2⁹
Block offset = 3 (From 2³)
Tag = (Memory address bit - block offset - Cache line bit)
Tag = (32 - 3 - 9)
Tag = 20
Total number of sets = 2⁹ = 512
Answer:
Because you could also receive shock
Explanation:
Automatic external defibrillators can help save lives during sudden cardiac arrest.
Do not touch the person while the AED is analyzing; touching or moving the person can affect the analysis. You or another person could be injured by shock. And you could prevent the AED from analyzing your heart rate correctly.
Answer:
The answer to this question is given below in the explanation section.
Explanation:
Consider the following method.
public double secret(int x, double y)
{
return x/2.0;
}
The return type of this function is double, so where it will store the result in a variable, that variable should be of double type. So, among given options, the correct option is double result = secret(4, 4.0);
All others options are incorrect and will give the error.
for example:
int result = secret(4, 4);
in it, the function secret is accepting first integer and second double parameters, while you are passing all integer variables.
int result = secret(4, 4.0);
you are not allowed to store double value into integer.
double result = secret(4.0, 4.0); in it you are passing incorrect types of parameter.