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Zarrin [17]
3 years ago
14

Evaluate: |6|+|-2∣. Answer value

Mathematics
2 answers:
solong [7]3 years ago
8 0

Answer:

8

Step-by-step explanation:

Absolute value of 6 is 6. Absolute value of -2 is 2. 6+2 is 8.

boyakko [2]3 years ago
4 0

Answer:

<h2>8</h2>

Step-by-step explanation:

\left|6\right|+\left|-2\right|\\\\\mathrm{Apply\:absolute\:rule}:\quad \left|a\right|=a,\:a\ge 0\\\\\left|6\right|=6\\=6+\left|-2\right|\\\mathrm{Apply\:absolute\:rule}:\quad \left|-a\right|=a\\\\\left|-2\right|=2\\=6+2\\\\Simplify\\=8

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Korolek [52]
It would round to 70,000
5 0
3 years ago
Please help I will give Brainliest please!
WITCHER [35]

Part (a)

The domain is the set of allowed x inputs of a function.

The graph shows that x = 0 is not allowed because of the vertical asymptote located here. It seems like any other x value is fine though.

<h3>Domain: set of all real numbers but x \ne 0</h3>

To write this in interval notation, we can say (-\infty, 0) \cup (0, \infty) which is the result of poking a hole at 0 on the real number line.

--------------

The range deals with the y values. The graph makes it seem like it stretches on forever in both up and down directions. If this is the case, then the range is the set of all real numbers.

<h3>Range: Set of all real numbers</h3>

In interval notation, we would say (-\infty, \infty) which is almost identical to the interval notation of the domain, except this time of course we aren't poking at hole at 0.

=======================================================

Part (b)

<h3>The x intercepts are x = -4 and x = 4</h3>

We can compact that to the notation x = \pm 4

These are the locations where the blue hyperbolic curve crosses the x axis.

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Part (c)

<h3>Answer: There aren't any horizontal asymptotes in this graph.</h3>

Reason: The presence of an oblique asymptote cancels out any potential for a horizontal asymptote.

=======================================================

Part (d)

The vertical asymptote is located at x = 0, so the equation of the vertical asymptote is naturally x = 0. Every point on the vertical dashed line has an x coordinate of zero. The y coordinate can be anything you want.

<h3>Answer: x = 0 is the vertical asymptote</h3>

=======================================================

Part (e)

The oblique or slant asymptote is the diagonal dashed line.

It goes through (0,0) and (2,6)

The equation of the line through those points is y = 3x

If you were to zoom out on the graph (if possible), then you should notice the branches of the hyperbola stretch forever upward but they slowly should approach the "fencing" that is y = 3x. The same goes for the vertical asymptote as well of course.

<h3>Answer:  Oblique asymptote is y = 3x</h3>
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Read 2 more answers
The perimeter of the rectangle is 146 units. What is the length of the longer side?
NeTakaya

we know that

the perimeter of the rectangle is equal to

P=2W+2L

where

P is the perimeter of the rectangle

W is the width of the rectangle

L s the length of the rectangle

In this problem

P=146\ units \\ W=2x\\ L=3x+3

Substitute the values in the formula above

P=2W+2L\\ 146=2*(2x)+2*(3x+3)\\ 73=2x+3x+3\\ 5x=70\\ x=14\ units

W=2x=2*14=28\ units\\ L=3x+3=3*14+3=45\ units

therefore

the answer is

the length of the longer side of the rectangle is equal to 45\ units

7 0
3 years ago
Read 2 more answers
How do I solve these two?
Bas_tet [7]

Answer:

1.D

2.B

Step-by-step explanation:

For the first one divide see which one is less which is D

For the second one Ive always used the method kcf keep change flip so you keep \frac{15}{1} the change ÷ to multiplication so then flip \frac{2}{9} so the equation would be

\frac{15}{1}x\frac{9}{2} so multiply the 15 by 9 then you get 135 then divide by 2 so thats your answer

8 0
3 years ago
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