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3 years ago

Which set does not contain –3?

Mathematics

2 answers:

kicyunya [14]3 years ago

7 0

Answer:

the set of all whole numbers

hope this helps!

dybincka [34]3 years ago

6 0

    Number - 3 is a real number and also a rational number.
    Whole numbers are: the numbers: 0, 1, 2, 3, ...
    Integers are like the whole numbers, but they also include negative numbers ( as - 3 ).
    So - 3 is an integer and not a whole number.
    Answer:
    C ) the set of whole numbers.

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3 years ago

What is the quotient of 3 divided 1/6

Bess [88]

Answer:

To find the quotient of 3 divided by 1/6 you must multiply by the reciprocal of the fraction, in this case it is 6.

So you would rewrite it as,

3*6=18

So your answer is multiply 3 by 6.

P.S * represents multiplication.

Step-by-step explanation:

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3 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

The managers of 21 supermarkets counted the number of cars in their parking lots on the same day. The results are shown in the l

mixer [17]

The IQR is 42.5

Step-by-step explanation:

Interquartile range is the difference of third and first quartile.

First of all we have to find the median for that purpose the data has to be arranged in ascending order. The data is already in ascending order.

As the number of values are odd

n=21

The median will be: $(\frac{n+1}{2}) th\ term$

Putting n=21

$(\frac{21+1}{2})th\ term\\=(\frac{22}{2})th\ term\\= 11th\ term$

The 11th term is 133

So median = 133

Now the data is divided into two halves

One is: 98, 100, 101, 102, 108, 109, 111,118, 129, 132

2nd is: 135, 135, 145, 146, 146, 156, 170 176, 180, 180

Q1 will be the median of first half and Q3 will be the median of 2nd half.

As now the halves contain even number of values, the medians will be the average of middle two values

For First Half:

98, 100, 101, 102, 108, 109, 111,118, 129, 132

$Q_1 = \frac{108+109}{2}\\Q_1 = \frac{217}{2}\\Q_1 = 108.5$

For Second Half:

135, 135, 145, 146, 146, 156, 170 176, 180, 180

$Q_2 = \frac{146+156}{2}\\Q_2 = \frac{302}{2}\\Q_2 = 151$

Now

Interquartile Range:

$IQR = Q_3-Q_1\\= 151-108.5\\=42.5$

Hence,

The IQR is 42.5

Keywords: Median, IQR

Learn more about median at:

#LearnwithBrianly

7 0

3 years ago