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2 years ago

1.2: Fractions of a Degree What temperature is shown on each thermometer?

Mathematics

1 answer:

Tom [10]2 years ago

5 0

Answer:

C=5/9(F-32)

Step-by-step explanation:

there you go

You might be interested in

Find the value of: (p+q)^0+1^p+q

MrMuchimi

Answer: 2+q

Step-by-step explanation:

6 0

3 years ago

mr and mrs gracia took their three children to see a matinee on saturday. they spent a total of 55.50, which included 29.95 at t

andrezito [222]

First, you would subtract 29.95 from 55.50, and you get 25.55. because 5 people went, and the cost for each was the same, you would divide 25.55 by five, and get $5.11 per person.

3 0

3 years ago

1. Write the form of the partial fraction decomposition of the rational expression. Do not solve for the constants.

german

Answer:

Step-by-step explanation:

To write the form of the partial fraction decomposition of the rational expression:

We have:

$\mathbf{\dfrac{8x-4}{x(x^2+1)^2}= \dfrac{A}{x}+\dfrac{Bx+C}{x^2+1}+\dfrac{Dx+E}{(x^2+1)^2}}$

Using partial fraction decomposition to find the definite integral of:

$\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}dx$

By using the long division method; we have:

$x^2-8x-20 | \dfrac{2x}{2x^3-16x^2-39x+20 }$

$- 2x^3 -16x^2-40x$

$x+ 20$

So;

$\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}= 2x+\dfrac{x+20}{x^2-8x-20}$

By using partial fraction decomposition:

$\dfrac{x+20}{(x-10)(x+2)}= \dfrac{A}{x-10}+\dfrac{B}{x+2}$

$= \dfrac{A(x+2)+B(x-10)}{(x-10)(x+2)}$

x + 20 = A(x + 2) + B(x - 10)

x + 20 = (A + B)x + (2A - 10B)

Now; we have to relate like terms on both sides; we have:

A + B = 1 ; 2A - 10 B = 20

By solvong the expressions above; we have:

$A = \dfrac{5}{2}$ $B = \dfrac{3}{2}$

Now;

$\dfrac{x+20}{(x-10)(x+2)} = \dfrac{5}{2(x-10)} + \dfrac{3}{2(x+2)}$

Thus;

$\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}= 2x + \dfrac{5}{2(x-10)}+ \dfrac{3}{2(x+2)}$

Now; the integral is:

$\int \dfrac{2x^3-16x^2-39x+20}{x^2-8x-20} \ dx = \int \begin {bmatrix} 2x + \dfrac{5}{2(x-10)}+ \dfrac{3}{2(x+2)} \end {bmatrix} \ dx$

$\mathbf{\int \dfrac{2x^3-16x^2-39x+20}{x^2-8x-20} \ dx = x^2 + \dfrac{5}{2}In | x-10|\dfrac{3}{2} In |x+2|+C}$

3. Due to the fact that the maximum words this text box can contain are 5000 words, we decided to write the solution for question 3 and upload it in an image format.

Please check to the attached image below for the solution to question number 3.

4 0

3 years ago

How can you tell if a relationship is proportiond?

VashaNatasha [74]

A relationship is proportional if they represent the same kind of relationship.

One way to tell if it is proportioned is to write them as fractions and then reduce them. If the reduced fractions are the same, the relationship is proportional.

6 0

3 years ago

(4x)(3z+y)+2x(3y+2z)=axz +bxy. Determine the values of a, b, and c

olganol [36]

Answer:

a = 16

b = 10

In the equation from the question there's no value that you can determine for c.

Step-by-step explanation:

(4x)(3z+y)+2x(3y+2z)=axz+bxy
12xz+4xy+6xy+4xz
16xz+10xy

5 0

3 years ago