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Monica [59]
3 years ago
6

Suppose g (x) is increasing and concave up everywhere and g(A)=7, gprime(A)=13, h=.01

Mathematics
1 answer:
rewona [7]3 years ago
8 0
First we need a point (x,y) : (A, 7) 
<span>Now slope (from f'(A)) = 15 </span>
<span>Next, the equation (using point slope formula) </span>

<span>y - 7 = 15 (x -A) </span>
<span>y = 15 (x - A) + 7 </span>

<span>Now in the x spot we put 'A-.01' </span>
<span>y = 15 ( A - .01 - A) +7= 15(-.01) +7 = -.15+ 7 = 6.85 
hope this helps</span>
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Step-by-step explanation:

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I NEED HELP ASAP <br><br> APEX!!!
igor_vitrenko [27]

The series will be:

4+16+64+.......+2^{50}

Hence, Option A is the right answer

Step-by-step explanation:

The series can be fount out by putting the values of i in the expression written with the summation

The expression is:

2^{2i}

while i = 1 to 25

Putting i = 1

2^{2(1)}\\= 2^2\\= 4

Putting i = 2

2^{2(2)}\\= 2^4\\= 16

Putting i = 3

2^{2(3)}\\= 2^6\\= 64

....

Putting i = 25

2^{2(25)}\\= 2^{50}

The series will be:

4+16+64+.......+2^{50}

Hence, Option A is the right answer

Keywords: Summation, Series

Learn more about summation at:

  • brainly.com/question/9381080
  • brainly.com/question/9532142

#LearnwithBrainly

6 0
3 years ago
Quadratic equations and complex numbers PLEASE HELPPPP ASAP
kondor19780726 [428]

we are given

27x^3-1=0

we can also write it as

(3x)^3-(1)^3=0

now, we can use factor formula

a^3-b^3=(a-b)(a^2+ab+b^2)

we can use above formula

we get  

(3x)^3-(1)^3=(3x-1)((3x)^2+3x\times 1+(1)^2)

now, we can simplify it

27x^3-1=(3x-1)(9x^2+3x+1)

now, we can set it to 0

27x^3-1=(3x-1)(9x^2+3x+1)=0

and then we can solve for x

(3x-1)(9x^2+3x+1)=0

3x-1=0

x=\frac{1}{3}

9x^2+3x+1=0

now, we can use quadratic formula

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

now, we can plug values

and we get

x=\frac{-3\pm \sqrt{3^2-4\cdot \:9\cdot \:1}}{2\cdot \:9}

x=-\frac{1}{6}+i\frac{\sqrt{3}}{6},\:x=-\frac{1}{6}-i\frac{\sqrt{3}}{6}

So, we will get solution as

x=\frac{1}{3},\:x=-\frac{1}{6}+i\frac{\sqrt{3}}{6},\:x=-\frac{1}{6}-i\frac{\sqrt{3}}{6}...............Answer

5 0
3 years ago
F(x)=2x^2+3 &amp; g(x)=x^2-7 find (f-g)(x)
kicyunya [14]

Answer:

\boxed{\sf (f - g)(x) = x^2 + 10}

Given:

f(x) = 2x² + 3

g(x) = x² - 7

To Find:

(f - g)(x)

Step-by-step explanation:

(f -g)(x) = f(x) - g(x)

= (2x² + 3) - (x² - 7)

= 2x² + 3 - x² + 7

= 2x² - x² + 3 + 7

= x² + 3 + 7

= x² + 10

5 0
3 years ago
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