Given:
Consider the expression are
1) 
2) ![\sqrt[3]{-8}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-8%7D)
3) 
4) ![\sqrt[3]{27}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27%7D)
To find:
The simplified form of each expression.
Solution:
1. We have,
Therefore, the value of this expression is 6.
2. We have,
![\sqrt[3]{-8}=(-8)^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-8%7D%3D%28-8%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
![\sqrt[3]{-8}=((-2)^3)^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-8%7D%3D%28%28-2%29%5E3%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
![\sqrt[3]{-8}=(-2)^{\frac{3}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-8%7D%3D%28-2%29%5E%7B%5Cfrac%7B3%7D%7B3%7D%7D)
![\sqrt[3]{-8}=-2](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-8%7D%3D-2)
Therefore, the value of this expression is -2.
3. We have,
Therefore, the value of this expression is -10.
4. We have,
![\sqrt[3]{27}=(27)^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27%7D%3D%2827%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
![\sqrt[3]{27}=(3^3)^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27%7D%3D%283%5E3%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
![\sqrt[3]{27}=(3)^{\frac{3}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27%7D%3D%283%29%5E%7B%5Cfrac%7B3%7D%7B3%7D%7D)
![\sqrt[3]{27}=3](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27%7D%3D3)
Therefore, the value of this expression is 3.
9 to the 3rd power is 729
And 2 to the 5th power is 32. You multiple 9, 3 times. 9 times 9 times 9 and you multiply 2, five times. 2 times 2 times 2 times 2 times 2
2 and 4 are both correct statements.
Answer:
See solution below
Step-by-step explanation:
According to pythagoras theorem
hyp^2 = opp^2 + adj^2
10^2 = 4^2 + b^2
100 = 16 + b^2
b^2 = 100-16
b^2 = 84
b = √84
b ≈ 9
Using SOH CHA TOA identity
sin B = AC/AB
Sin B = 9/10
B = arcsin0.9
B ≈ 64degrees
sinA = BC/AB
Sin A = 4/10
A = arcsin0.4
A ≈ 24degrees
12 divided by 2/3 = 18
2/3 divided by 12 = 0.5
