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Svetradugi [14.3K]
3 years ago
15

Farmer bob's square plot ofland is slowly eroding away. Worried about the future of his farm. Farmer Bob measures the rate of er

osion and finds that the length of each side of his square plot is decreasing at the constant rate of 2 feet/year. If he currently owns 250,000 square feet of land, what is the current rate of change of the area of Farmer Bob's land?
a) Farmer bob is losing 2,000 square feet of land per year
b) losing 1,000,000 square feet of land per year
c) losing 1,000 square feet of land per year
d) losing 4 square feet of land per year
Mathematics
1 answer:
kow [346]3 years ago
7 0

Answer:

Option A.

Step-by-step explanation:

Area of a square is

A=x^2               .... (1)

where, x is side length.

The length of each side of his square plot is decreasing at the constant rate of 2 feet/year.

\dfrac{dx}{dt}=2

It is given that bob currently owns 250,000 square feet of land.

Fist find the length of each side.

A=250000

x^2=250000

Taking square root on both sides.

x=500

Differentiate with respect to t.

\dfrac{dA}{dt}=2x\dfrac{dx}{dt}

Substitute x=500 and \frac{dx}{dt}=2 in the above equation.

\dfrac{dA}{dt}=2(500)(2)

\dfrac{dA}{dt}=2000

Farmer bob is losing 2,000 square feet of land per year.

Therefore, the correct option is A.

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SSSSS [86.1K]

Answer:

C (y=5x-7)

Step-by-step explanation:

First, you find the slope between the 2 points which is 5, then you use one of the points to form an equation.  

You then find it's y=5x-7.

8 0
3 years ago
Please solve the whole page please please
Leya [2.2K]

1d) ↑ (Do the same but turned if that's easier)

1a) 199

1b) 193

1c) 217

1e) Based on the box plot, we can for example, find the lowest and greatest values, the range (largest - smallest), the mean (all values / # values), and the median middle value or q2 given by the second line in the box.

2b) 7

2c) 9.5

2d) ↑

2e) because the data is not ordered, it is difficult to determine the quartile data. Once it is ordered like 6, 7, 7, 7, 8, 8, 9, 10, 10. The data can be visualized alot easier. With the box plot we can determine q3 of the data by looking at the 3rd line, using the whiskers of the box to find the minimum and maximum values.

3)

You need to find the minimum, maximum, the quartile data obtained by having an even amount of data on both sides, order it so that values can be grouped. this includes q1, q2 (or median), and q3.

In this case the ordered data would be: 4,6,8,8,9,11,12,14,14,16.

[4, 6, 8, 8, 9] [] [11, 12, 14, 14, 16]

4 is the minimum, 16 is the maximum, q1 is 8, q3 is 14, and median is 10.

4) ↑

5)

You need to find the minimum, maximum, the quartile data obtained by having an even amount of data on both sides, order it so that values can be grouped. this includes q1, q2 (or median), and q3.

In this case the ordered data would be:

45, 45, 50, 55, 60, 70, 70, 75, 80, 85

[45, 45, 50, 55, 60] [] [70, 70, 75, 80, 85]

45 is the minimum, 85 is the maximum, q1 is 50, q3 is 75, and median is 65.

6) ↑

4 0
2 years ago
In a school with 200 students, 45% are males. how many males are there.? please help me​
LUCKY_DIMON [66]

Answer:

<u><em>90 males.</em></u>

Step-by-step explanation:

To find the answer we will <u><em>divide 45% by 100</em></u>, and we get <u><em>0.45</em></u>.  Now <u><em>multiply 0.45 by 200</em></u> and you get <u><em>90</em></u>.  Therefore, <u><em>90 males is the answer. </em></u>

7 0
3 years ago
A survey was done to investigate the relationship between liking math and learning a musical
Brrunno [24]

Answer:

c

Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
Greg is trying to solve a puzzle where he has to figure out two numbers, x and y. Three less than two-third of x is greater than
Fittoniya [83]
Inequation 1: 

\frac{2}{3}x-3 \geq y

to plot the pairs (x, y) for which the inequation holds, draw the line y=\frac{2}{3}x-3

then pick a point in either side of the line. If that point is a solution of the inequation, than color that region of the line, if that point is not a solution, then color the other part of the line.

we do the same for the second inequation. Then the solution, is the region of the x-y axes colored in both cases.

inequation 2: 

y+ \frac{2}{3}x\ \textless \ 4

y\ \textless \ - \frac{2}{3} x+ 4&#10;


draw the lines 

i)  y=\frac{2}{3}x-3          use points (0, -3),  (3, -1)

ii)y=- \frac{2}{3} x+ 4       use points ( 0, 4),   (3, 2)


let's use the point P(3, 3) to see what region of the lines need to be coloured:

\frac{2}{3}x-3 \geq y  ; 
\frac{2}{3}(3)-3 \geq 3
2-3 \geq 3, not true so we color the region not containing this point


y+ \frac{2}{3}x\ \textless \ 4
(3)+ \frac{2}{3}(3)\ \textless \ 4
3+ 5\ \textless \ 4 not true, so we color the region not containing the point (3, 3)

The graph representing the system of inequalities is the region colored both red and blue, with the blue line not dashed, and the red line dashed.



4 0
3 years ago
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