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loris [4]
3 years ago
15

Sarah has a 22 ounce lemonade. She drinks 9 ounces. Enter the percentage of ounces Sarah has left of her lemonade. Round your an

swer to the nearest hundredth.
Mathematics
2 answers:
blagie [28]3 years ago
7 0

Answer:

40.91 percent

Korvikt [17]3 years ago
6 0
22-9= 13 divided by 22= 60%
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Factor the expression 9x^2 - 30x + 25 I need help
MrMuchimi

Answer:

(3x - 5)²

Step-by-step explanation:

When we expand (3x - 5)², we get:

(3x - 5) (3x - 5)

When we multiply, we get:

9x² - 30x + 25

---------------------------------------------------------------------------------------------------------------

Have a great summer :)

7 0
3 years ago
SYSTEMMMMMMM OF A EQUATIONSSSSSSSSSSSSSSSSSSSSSSSSS
Shtirlitz [24]

Answer: B maybe i hope this was help

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Assume that it costs Apple approximately E(x) 25,600 + 100x + 0.012 dollars to manufacture x 32GB iPods in a day. (a) The averag
uranmaximum [27]

Answer:

(a)C'(x)=\dfrac{x^2-2560000}{x^2}

(b)x=1600, Minimum Average Cost Per iPod=$132

(c)C''(x)=\dfrac{5120000}{x^3}

The result, C''(1600) is positive, which means that the average cost is Concave up at the critical point, and the critical point is a minimum.

Step-by-step explanation:

Given that it costs Apple approximately $ C(x) to manufacture x 32GB iPods in a day, where:

C(x)=25,600+100x+0.01x^2

(a)The average cost per iPod when they manufacture x iPods in a day is given by:

Cost \:Per \:iPod=\dfrac{C(x)}{x} =\dfrac{25,600+100x+0.01x^2}{x}

The average cost per iPod is therefore:

C'(x)=\dfrac{x^2-2560000}{x^2}

(b)To minimize average cost of x iPods per day, we set the average cost per iPod=0 and solve for x.

C'(x)=\dfrac{x^2-2560000}{x^2}=0\\x^2-2560000=0\\x^2=2560000\\x=\sqrt{2560000}=1600

The resulting minimum average cost (at x=1600) is given as:

Cost \:Per \:iPod=\dfrac{C(x)}{x} =\dfrac{25,600+100x+0.01x^2}{x}\\\dfrac{25,600+100(1600)+0.01(1600)^2}{1600}\\=\$132

<u>Second derivative test</u>

(c)The answer above is a critical point for the average cost function. To show it is a minimum, we calculate the second derivative of the average cost function.

C''(x)=\dfrac{5120000}{x^3}

At the critical point,  x=1600

C''(1600)=\dfrac{5120000}{1600^3}=0.00125

The result, C''(1600) is positive, which means that the average cost is Concave up at the critical point, and the critical point is a minimum.

3 0
3 years ago
115 and 125 as a decimal
Nitella [24]
0.92.................
3 0
3 years ago
Please help me with this math problem
Alex_Xolod [135]

Answer:

x-intercept(s):  

(−8,0)

y-intercept(s):  

(0,6)

Step-by-step explanation:

5 0
3 years ago
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