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blsea [12.9K]
3 years ago
15

Find the volume of the figure

Mathematics
2 answers:
mina [271]3 years ago
7 0

Answer:

It is C. 233 because if you multiply 5x5x5 thats 125

If you multiply 12x3x3, its 108. So add 108+125 and that will be your final answer. Hope this helps and if so then please mark as brainliest. Remember that volume= length x width x height.

nevsk [136]3 years ago
7 0

Answer:

C

Step-by-step explanation:

3 x 3 x 12 = 108

5 x 5 x 5 = 125

125 + 108 = 233

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6(q − 87) = 36 what does q equal?
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Answer:q=-81

Step-by-step explanation:6(q-87)=36

6q-522=36

-522 from each side

6q=-486

Divide 6 from each side

q=-81

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The altitude to the hypotenuse of a right triangle is the geometric mean between the segments on the hypotenuse
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How to convert 0.6666666667 to a fraction
Arada [10]
If you got this answer from a calculator, it rounds the last decimal point because there is not enough room on it to show that it is a repeating decimal.

Really, the decimal is .666666666666...... , or 2/3

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4 0
3 years ago
We roll two fair 6-sided dice. Each of the 36 possible outcomes is assumed to be equally likely. (a) Given that the roll results
boyakko [2]

Answer:

a) \frac{1}{7}

b) \frac{2}{15}

Step-by-step explanation:

Given : We roll two fair 6-sided dice. Each of the 36 possible outcomes is assumed to be equally likely.

The outcomes are :

(1, 1) (1, 2)  (1, 3)  (1, 4)  (1, 5)  (1, 6)

(2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)

(3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)

(4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)

(5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6)

(6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)

(a) Given that the roll results in a sum of 3 or more, find the conditional probability that doubles (the first and the second rolls result in the same number) are rolled.

Let P(A) be the probability of event that the roll results in a sum of 3 or more.

Except (1,1) rest sum is 3 or greater than 3.

So, P(A)=\frac{35}{36}

Now, P(A and B) is that the roll results in a sum of 3 or more and that doubles (the first and the second rolls result in the same number) are rolled.

i.e. (2,2), (3,3), (4,4), (5,5), (6,6) - 5

P(A\cap B)=\frac{5}{36}

The conditional probability is given by,

P(B|A)=\frac{P(A\cap B)}{P(A)}

P(B|A)=\frac{\frac{5}{36}}{\frac{35}{36}}

P(B|A)=\frac{5}{35}

P(B|A)=\frac{1}{7}

(b) Given that the two dice land on different numbers, find the conditional probability that the sum is 5.

Let P(A) be the probability of event that two dice land on different numbers.

Except (1,1),(2,2), (3,3), (4,4), (5,5), (6,6) rest two dice land on different numbers.

So, P(A)=\frac{30}{36}

Now, P(A and B) is that two dice land on different numbers and the sum is 5.

i.e. (1,4), (2,3), (3,2), (4,1) - 4

P(A\cap B)=\frac{4}{36}

The conditional probability is given by,

P(B|A)=\frac{P(A\cap B)}{P(A)}

P(B|A)=\frac{\frac{4}{36}}{\frac{30}{36}}

P(B|A)=\frac{4}{30}

P(B|A)=\frac{2}{15}

4 0
3 years ago
Given that BE=6, CE=6,<br>and FE measures 5 more<br>than DE, find the length<br>of DE.​
katen-ka-za [31]

Answer:

DE = 4 units.

Step-by-step explanation:

By the chord intersection theorem:

BE * CE = DE * FE

But FE = DE + 5 so:

BE * CE = DE * (DE + 5)

6 * 6 = DE^2 + 5DE

DE^2 + 5DE  - 36 = 0

(DE + 9)(DE - 4) = 0

So DE = -9 or 4

It can't be negative so DE = 4.

4 0
4 years ago
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