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3 years ago

Can someone please answer 11 and 13 for me? its quadratics by factoring.

Mathematics

1 answer:

poizon [28]3 years ago

5 0

11. 7, or -1
you are setting it so it's equal to 0
There is no work being done. You just need to set one or both equations up so it equals 0
0(x) will always be 0

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Question 2 Write the following paragraph proof as a two-column proof. Given: AB = CD and BC = DE Prove: AC = CE A B C D E We're

alex41 [277]

Answer: See below

Step-by-step explanation:

<u>Given:</u>

AB = CD and BC = DE

<u>To prove:</u>

AC = CE

Statements Reasons

AB = CD Given
AB + CB = CD + BC Addition property of equality
AB + BC = CD + DE Given: BC = DE
AC = CE By segment addition: AB + BC = AC and CD + DE = CE

Therefore, AC = CE has been proved

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2 years ago

F a company provides 1 1/4 vacation days to its employees every month, how many vacation days does an employee get every year?

Morgarella [4.7K]

1 1/4 per month

12 months per year

1 1/4 * 12 =

5/4 * 12/1 = 60/4 = 15

they get 15 days per year

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4 years ago

What is the highest common factor of 45 and 315?

7nadin3 [17]

The highest common factor is 45

8 0

3 years ago

Read 2 more answers

Use technology or a z-score table to answer the question.

Alik [6]

Answer:

The second choice: Approximately $65.2\%$ of the pretzel bags here will contain between 225 and 245 pretzels.

Step-by-step explanation:

This explanation uses a z-score table where each $z$ entry has two decimal places.

Let $\mu$ represent the mean of a normal distribution of variable $X$ . Let $\sigma$ be the standard deviation of the distribution. The z-score for the observation $x$ would be:

$\displaystyle z = \frac{x - \mu}{\sigma}$ .

In this question,

$\mu = 240$ .
$\sigma = 9.3$ .

Calculate the z-score for $x_1 = 225$ and $x_2 = 245$ . Keep in mind that each entry in the z-score table here has two decimal places. Hence, round the results below so that each contains at least two decimal places.

$\begin{aligned} z_1 &= \frac{x_1 - \mu}{\sigma} \\ &= \frac{225 - 240}{9.3} \approx -1.61\end{aligned}$ .

$\begin{aligned} z_2 &= \frac{x_2 - \mu}{\sigma} \\ &= \frac{245 - 240}{9.3} \approx 0.54\end{aligned}$ .

The question is asking for the probability $P(225 \le X \le 245)$ (where $X$ is between two values.) In this case, that's the same as $P(-1.61 \le Z \le 0.54)$ .

Keep in mind that the probabilities on many z-table correspond to probability of $P(Z \le z)$ (where $Z$ is no greater than one value.) Therefore, apply the identity $P(z_1 \le Z \le z_2) = P(Z \le z_2) - P(Z \le z_1)$ to rewrite $P(-1.61 \le Z \le 0.54)$ as the difference between two probabilities:

$P(-1.61 \le Z \le 0.54) = P(Z \le 0.54) - P(Z \le -1.61)$ .

Look up the z-table for $P(Z \le 0.54)$ and $P(Z \le -1.61)$ :

$P(Z \le 0.54)\approx 0.70540$ .
$P(Z \le -1.61) \approx 0.05370$ .

$\begin{aligned}& P(225 \le X \le 245) \\ &= P\left(\frac{225 - 240}{9.3} \le Z \le \frac{245 - 240}{9.3}\right)\\&\approx P(-1.61 \le Z \le 0.54) \\ &= P(Z \le 0.54) - P(Z \le -1.61)\\ &\approx 0.70540 - 0.05370 \\& \approx 0.65.2 \\ &= 65.2\% \end{aligned}$ .

3 0

4 years ago

According to this map of railroads in 1890, what part of country were most

Rashid [163]

Answer:

In 1890, America's railroad linked mainly through the north and south rarely in the west if at all.

7 0

3 years ago