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3 years ago

Which answer best describes the solution to the equation

Mathematics

1 answer:

leonid [27]3 years ago

6 0

$3m-9=9+3m \\
3m-3m=9+9 \\
0=18 \\
\hbox{not true}$

The answer is B. no solution.

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Please give a step by step solution on how to solve #5. Thanks!

Zina [86]

Rate of burn(scented):1/8inch in 1/4h
=4(1/8)inch in 1h=1/2inch in 1h

Rate of burn(unscented):1/9inch in 1/3h=3(1/9)inch in 1h=1/3inch in 1h

The scented candle burns more in one hour.

1/2inch-1/3inch=1/6inch

The scented candle burns 1/6inch more per hour

7 0

3 years ago

A number with 2 decimal places, that is bigger than 4 1/5 but smaller than 4.25

LUCKY_DIMON [66]

Answer:

4.21, 4.22, 4.23,

4.24 (choose any one)

Step-by-step explanation:

since 4 1/5 is 4.20, so the numbers in between 4.20 and 4.25 are 4.21, 4.22, 4.23,

4.24 (choose any one)

3 0

3 years ago

What is the sum of three tenths plus thirty nine hundredths equals blank a thirty six hundredths b forty two hundredths c sixty

ad-work [718]

Answer:c- sixty nine hundredths

Step-by-step explanation:

three tenths can be expressed in decimal as 3/10

thirty nine hundredths can be expressed in decimal as 39/100

Therefore the sum of three tenths plus thirty nine hundredths equals

3/10 +39/100

We first find the l.c.m of the two fractions equals 100 so we have 100 as the denominator

then 100 divided by 10 multiplied by 3 +100 divided by 100 multiplied by 39 as illustrated below gives the answer

3/10 +39/100

=30+39/100

=69/100= sixty nine hundredths

3 0

3 years ago

Which table represents a function?

yawa3891 [41]

B represents a function ✔️

7 0

2 years ago

How do I solve: 2 sin (2x) - 2 sin x + 2√3 cos x - √3 = 0

ziro4ka [17]

Answer:

$\displaystyle x = \frac{\pi}{3} +k\, \pi$ or $\displaystyle x =- \frac{\pi}{3} +2\,k\, \pi$ , where $k$ is an integer.

There are three such angles between $0$ and $2\pi$ : $\displaystyle \frac{\pi}{3}$ , $\displaystyle \frac{2\, \pi}{3}$ , and $\displaystyle \frac{4\,\pi}{3}$ .

Step-by-step explanation:

By the double angle identity of sines:

$\sin(2\, x) = 2\, \sin x \cdot \cos x$ .

Rewrite the original equation with this identity:

$2\, (2\, \sin x \cdot \cos x) - 2\, \sin x + 2\sqrt{3}\, \cos x - \sqrt{3} = 0$ .

Note, that $2\, (2\, \sin x \cdot \cos x)$ and $(-2\, \sin x)$ share the common factor $(2\, \sin x)$ . On the other hand, $2\sqrt{3}\, \cos x$ and $(-\sqrt{3})$ share the common factor $\sqrt[3}$ . Combine these terms pairwise using the two common factors:

$(2\, \sin x) \cdot (2\, \cos x - 1) + \left(\sqrt{3}\right)\, (2\, \cos x - 1) = 0$ .

Note the new common factor $(2\, \cos x - 1)$ . Therefore:

$\left(2\, \sin x + \sqrt{3}\right) \cdot (2\, \cos x - 1) = 0$ .

This equation holds as long as either $\left(2\, \sin x + \sqrt{3}\right)$ or $(2\, \cos x - 1)$ is zero. Let $k$ be an integer. Accordingly:

$\displaystyle \sin x = -\frac{\sqrt{3}}{2}$ , which corresponds to $\displaystyle x = -\frac{\pi}{3} + 2\, k\, \pi$ and $\displaystyle x = -\frac{2\, \pi}{3} + 2\, k\, \pi$ .
$\displaystyle \cos x = \frac{1}{2}$ , which corresponds to $\displaystyle x = \frac{\pi}{3} + 2\, k \, \pi$ and $\displaystyle x = -\frac{\pi}{3} + 2\, k \, \pi$ .

Any $x$ that fits into at least one of these patterns will satisfy the equation. These pattern can be further combined:

$\displaystyle x = \frac{\pi}{3} + k \, \pi$ (from $\displaystyle x = -\frac{2\,\pi}{3} + 2\, k\, \pi$ and $\displaystyle x = \frac{\pi}{3} + 2\, k \, \pi$ , combined,) as well as
$\displaystyle x =- \frac{\pi}{3} +2\,k\, \pi$ .

7 0

3 years ago